All categories

3 years ago

What is the answer for 790 x 397 estimate

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

5 0

Answer:

320,000

Step-by-step explanation:

790 is almost 800

397 is almost 400

800*400 is 320,000

You might be interested in

Simplify 9 − (−4). −13 −5 5 13

olchik [2.2K]

Answer:

Step-by-step explanation:

two negatives make a positive

4 0

3 years ago

BONUS, Factor 1 - 64x^3 completely,

kvv77 [185]

Rewrite then factor as a difference of cubes:

1 - 64x³ = 1³ - (4x)³

= (1 - 4x) (1² + 4x + (4x)²)

= (1 - 4x) (1 + 4x + 16x²)

6 0

3 years ago

Which bar model could be used to show this situation?

9966 [12]

Answer:

C. The attached

Step-by-step explanation:

Our total is 44 dollars. This means that the largest bar, our whole, should be 44.

-> This rules out option D

Now, 4 sweatshirts are being bought. This means the 44 dollars should be broken up into 4 different parts since they all "cost the same amount of money."

-> This rules out options A, C, and D.

This leaves us with the correct option of option C.

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

8 0

2 years ago

Read 2 more answers

i need help with my homework plssssss stella drank 2/3 of her water on monday and on tuesday she drank 3/7 how much alltogether

mel-nik [20]

Answer:

1 2/21

Step-by-step explanation:

2/3 + 3/7

14/21+ 9/21= 23/21

5 0

3 years ago

EDU 2020

Tom [10]

Answer:

$\log_615=1.511$

$\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}4$

$\log_w \frac{x}{z}=\log_wx-\log_w z$

Step-by-step explanation:

By quotient property :

$\log_xa-\log_xb=\log_x\frac{a}{b}$

Given:

$\log_630\approx 1.898$ and $\log_62\approx 0.387$

To find $\log_615$

Solution:

Applying quotient property:

$\log_630-\log_62=\log_6\frac{30}{2}=\log_615$

$\log_615=\log_630-\log_62$

$\log_615=1.898-0.387$

$\log_615=1.511$

To write $\log_{14}6-\log_{14}\frac{3}{2}$ as a single logarithm.

Solution:

Applying quotient property:

$\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}\frac{6}{\frac{3}{2}}$

$\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}(6\times \frac{2}{3})$

$\log_{14}6-\log_{14}\frac{3}{2}=\log_{14}4$

To expand $\log_w \frac{x}{z}$

Solution:

Applying quotient property:

$\log_w \frac{x}{z}=\log_wx-\log_w z$

3 0

4 years ago

Read 2 more answers