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Ksju [112]
3 years ago
15

Lauren packs in order of blocks into crates and 7 steps how many blocks does Lauren pack

Mathematics
1 answer:
allsm [11]3 years ago
8 0
She needs 27 crates to make 7 steps. It makes more sense if you draw it out for yourself. 
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Plz help me i need 100%
leva [86]
The answer is D.) 5/7
7 0
3 years ago
Read 2 more answers
1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form
lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0
3 years ago
Please help!!<br> Question is in the picture!!
Debora [2.8K]

\frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

<u>Experimental probabilities from the table:</u>

Probability of getting 1 = \frac{12}{60}=\frac{1}{5}

Probability of getting 2 = \frac{17}{60}

Probability of getting 3 = \frac{15}{60}=\frac{1}{4}

Probability of getting 4 = \frac{16}{60}=\frac{4}{15}

<u>To determine which are the experimental probabilities from the table:</u>

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: \frac{17}{60}

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: \frac{1}{4}

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: \frac{7}{15}

This is not obtained above. So, it is not the experimental probability.

Option E: \frac{12}{43}

This is not obtained above. So, it is not the experimental probability.

Hence \frac{17}{60} and \frac{1}{4} are the experimental probabilities from the table.

5 0
3 years ago
HELP
Oksi-84 [34.3K]

the answer is D :) i hope you have a good day

4 0
3 years ago
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A coin is tossed three times. what is the probability of getting two heads and one tail?
Lera25 [3.4K]
If the order doesn't matter, then the probability is 37.5%
If it has to be head head tail, then the probability is 12.5%

If the order doesn't matter, the possible outcomes that have two heads and one tail are HHT, HTH, and THH. Since these all have a probability of 12.5% of occuring, the probability of any of them occuring is 37.5%
7 0
3 years ago
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