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Burka [1]
3 years ago
10

Your car broke down and the final bill was 261.50 the part that was replaced cost 99 and the charge for the mechanics labor is 6

5 per hour write an inequality to model this situation then solve the equation for the number of hours the mechanic worked on your car
Mathematics
1 answer:
Tanya [424]3 years ago
4 0
Your inequality would be 261.50 less than or equal to 65x+ 99

now to solve this you would begin by isolating 65x you would do this by subtracting 99 on both sides.

162.50 less than or equal to 65x

to get x alone [because thats what youre solving for] you need to divide by 65 on both sides.

x= 2.5

Now you can check youre work

261.50 less than or equal to 65(2.5) + 99

youll get 

261.50 less than or equal to 261.50
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The length of a rectangle is 5.9 cm more than 3 times the width. If the perimeter of the rectangle is 57.4cm, what are it's dime
navik [9.2K]

Answer:

l = 23 cm and w = 5.7 cm

Step-by-step explanation:

Perimeter = twice the length plus twice the width

let w = width

let l = length

l = 5.9 + 3w

57.4 = 2(5.9 + 3w) + 2w

57.4 = 11.8 + 6w + 2w

57.4 = 11.8 + 8w

45.6 = 8w

w = 5.7

Substitute 5.7 for 'w' to get 'l':

l = 5.9 + 3(5.7)

l = 23

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3 years ago
4w-3(-5z+2w)-2z
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Which of the following is the equation of a line that passes through the points (2,5) and (4,3)?
kondor19780726 [428]

Answer:

Step-by-step explanation:

5 0
3 years ago
Contestants in a dance marathon rest for the same amount of Time ever hour. A couple rest for 27 minutes in 6 hours. How long do
sergejj [24]

Answer:

they rest for 36 minutes

Step-by-step explanation:

27 minutes        x

----------------- = ---------------

6 hrs                    8 hrs

using cross products

27 * 8 = 6x

divide by 6

27*8/6 = x

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3 0
3 years ago
A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

7 0
3 years ago
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