→ 6x² - 2x - 20
→ 6x² + 10x - 12x - 20
→ x(6x + 10 ) - 2 (6x + 10)
→ (6x + 10) (x - 2) .
for
6x - 10 = 0
6x = 10
for x - 2
x = 2
False, it's always on the vertex of the parabola.
8x + 16 = 14x
To solve this equation, move everything containing the variable you want to solve for on one side of the equation and everything else to the other side of the equation.
Let's start by subtracting 8x from both sides to have the variable x all on the right side of the equation. Once you subtract 8x from both sides, your equation will now look like this:
16 = 6x
To solve for the variable x, you want to divide both sides of the equation by 6 to isolate x and therefore find your answer. Divide both sides by 6 and your equation should look like this:
16/6 = x
Simplifying 16/6 into a mixed number ⇒ 2 2/3
Your answer is x = 16/6 or 2 2/3.
Answer:
B., E.
Step-by-step explanation:
what was the difficulty ? this is just to understand the movement of a thrown rock.
what happens, when you throw a rock through the air ? it will first move up a little bit, reaches a maximum height, and then drops down again.
that is what the graphic shows.
so, can A. be correct ? no. as we move from 0 seconds to the right (time passes) the height of the rock increases first (before decreasing again later on).
can C. be correct ? no, it would mean that the function would look the same on both sides of the x-axis. this is clearly impossible.
can D. be correct ? no, nowhere in the graph is the height (= the functional value, the y to the x) negative.
can F. be correct ? no, we clearly see the maximum height at 1.5 seconds. at 3 seconds the height is actually at its minimum.
Step-by-step explanation:
answer A is correct
................
