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Agata [3.3K]
3 years ago
9

A streetlight that is 8 feet tall casts a 3-foot-long shadow. A nearby flagpole casts a 15-foot-long shadow. What is the height

of the flagpole?
Mathematics
2 answers:
Brut [27]3 years ago
6 0

Answer:

20 Feet

Step-by-step explanation:

Marina86 [1]3 years ago
6 0

Answer:

40 feet

Step-by-step explanation:

15 / 3 = 5

5 x 8 = 40

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Romashka [77]

Answer:

\dfrac{dy}{dx}=-\dfrac{2x-y-1}{2y-x-1}

Step-by-step explanation:

Differentiating, you get ...

... x·dy +y·dx +dx +dy = 2x·dx +2y·dy

Collecting terms gives ...

... dy(x +1 -2y) = dx(2x -y -1)

... dy/dx = -(2x -y -1)/(2y -x -1)

4 0
3 years ago
5x-1≥-4(x+7)<br><br> solve... please
amid [387]

Answer: x ≥ - 3

5x - 1 ≥ -4(x + 7)

⇔ 5x - 1 ≥ - 4x -28

⇔ 5x + 4x ≥ - 28 + 1

⇔ 9x ≥ - 27

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Step-by-step explanation:

3 0
3 years ago
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A negative angle or a positive angle may be used to represent the same thing.
miss Akunina [59]

Answer:

1.Sometimes

Step-by-step explanation:

If it is π it represents samething otherwise it does not.

8 0
3 years ago
All athletes at the Olympic Games (OG) are tested for performance-enhancing steroid drug use. The basic Anabolic Steroid Test (A
Semenov [28]

Answer:

a ) the probability of using steroids and having a negative test is 0.5%

b) The probability of testing positive is 6.4%

c) The probability of not using steroids, given that the test is negative is 99.47%

d) No, they are not statistically indepent.

e) The probability that the athlete will either use steroids or test positive is 6.9%

Step-by-step explanation:

Let A be the event that the test result is positive and B the event that the athlete uses Steroids. We are given the following

P(A|B) = 90%, P(A|B^c) = 2%, P(B) = 5%

From which we deduce that

P(A^c|B) = 10%, P(B^c) = 95%

a) We are asked for the probability P(A^c\cap B). REcall the conditional probability formula that, given two events C,D the conditional probability P(C|D) = \frac{P(C\cap D)}{P(D)}. Then we have that

P(A^c\cap B) = P(A^c|B)P(B) = 10\% \cdot 5\%=0.5\%.

b) We are asked for the probability P(A). We can use the fact that given two mutually exclusive events(that is, whose intersection is empty) A,B the probability P(C) of an event is given by P(C) = P(C|A)P(A)+P(C|B)P(B). Then

P(A) = P(A|B)P(B)+P(A|B^c)P(B^c) = 90\%\cdot5\% + 2\% \cdot 95% = 6.4\%

c) We are asked for the probability P(B^c|A^c). Recall that P(A|B) = \frac{P(B|A)P(A)}{P(B)}. Then

P(B^c|A^c) = \frac{P(A^c|B^c)P(B^c)}{P(A^c)}= \frac{P(A^c|B^c)P(B^c)}{1-P(A)}= \frac{(1-P(A|B^c))P(B^c)}{1-P(A)}=\frac{98\%\cdot 95\%}{1-6.4\%}= 99.47\%

d) We say that two events A,B are statistically indepent if P(A|B) = P(A). Note that from point B the probability of testing negative is 1- 6.4% = 93.6%. Since 93.6% is different from 99.47% this means that testing positive and using steroids are not statistically independent.

e) We are asked for the probability P(A\cup B). We use the following

P(A\cupB) = P(A)+P(B)-P(A\cap B) = P(A) +P(B)-P(A|B)P(B) = 6.4\%+5\%-90\%\cdot 5\%=6.9\%

4 0
4 years ago
Identify the vertex and the axis of symmetry of the parabola. <br><br> HELP PLEASE!!!
jeka94

We know that the graph goes in units of 1.

We know that the roots are -1 and 4. (Just assume it's accurate and not off by 0.0000000001.)


We can set it up as an equation: -1(x+1)(x-4) = y (I added -1 because there are two parabolas that go through those points on the x-axis, and since this parabola is facing down, I must add a negative a value.


Then multiply (F.O.I.L. - First, Outer, Inner, Last)


x^2 -4x + x - 4 = -(x^2 - 3x - 4) = -x^2 + 3x + 4


Then using -(b/2a) solve for vertex: -(3/-2) = 3/2


Plug 3/2 back into the equation.

-(3/2)^2 + 3(3/2) + 4 = -9/4 + (9/2) + 4 = 25/4


The vertex would be: (3/2, 25/4)

Axis of symmetry would be: x = 3/2

8 0
4 years ago
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