1800:60=30 revolutions per second
30*2π=60π radians per second
Let: eq 1:2x+5y=-55
eq 2:y=3x+6
by substituting eq 2 in eq 1 we get,
2x+5(3x+6)=-55
2x+15x+30+55=0
17x + 85=0
x=-85/17
x=-5
By substituting x value in eq 2,
we have,
y=3(-5)+6=-15+6=-9
Answer:
always true.
the expression will always be equal to +5 because -p+p is zero
at any given value to p, the value is constantly +5
Answer:
D
Step-by-step explanation:
Answer:
![WoodLength = 50w + 20](https://tex.z-dn.net/?f=WoodLength%20%3D%2050w%20%2B%2020)
Step-by-step explanation:
Given
Length of Pieces = 50cm
Number of Pieces = w
Left over = 20cm
Required
Determine the length of the wood
Start by multiplying the number of pieces by the length of each pieces
![Result = Length * Number](https://tex.z-dn.net/?f=Result%20%3D%20Length%20%2A%20Number)
![Result = 50 * w](https://tex.z-dn.net/?f=Result%20%3D%2050%20%2A%20w)
![Result = 50 w](https://tex.z-dn.net/?f=Result%20%3D%2050%20w)
Lastly, add the leftover to get the actual length of the wood
![Wood Length = Result + Leftover](https://tex.z-dn.net/?f=Wood%20Length%20%3D%20Result%20%2B%20Leftover)
Substitute 50w for Result and 20 for Leftover
![WoodLength = 50w + 20](https://tex.z-dn.net/?f=WoodLength%20%3D%2050w%20%2B%2020)
<em>Hence, the length of the wood is 50w + 20</em>