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Olenka [21]
1 year ago
6

Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation one-halfx2 4x 8 = 0. whi

ch explanation could anderson provide?
Mathematics
1 answer:
amid [387]1 year ago
3 0

Anderson could provide 0.5x2 + 4x + 8 = 0 has exactly one real root if the discriminant is 0,

<h3>What is quadratic equation?</h3>

Any equation that can be rewritten in standard form as where x represents an unknown, a, b, and c represent known numbers, and where a 0 is true is a quadratic equation. As there is no ax2 term when a = 0, the equation is linear rather than quadratic.

<h3>What is discriminant?</h3>

A polynomial's discriminant is a quantity that depends on the coefficients and enables for some root attributes to be inferred without actually computing them. It is actually a polynomial function of the original polynomial's coefficients.

<h3>According to the given information:</h3>

0.5x^2 + 4x + 8 = 0

The discriminant is computed utilizing:

d = b^2 - 4ac

Thus, we have:

d = 4^2 - 4 * 0.5 * 8

Evaluate

d = 0

The equation has only one real root since the discriminant is 0,

To know more about discriminant visit:

brainly.com/question/16369636

#SPJ4

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2. To estimate the mean age for a population of 4000 employees, a simple random sample of 40 employees is selected. a. Would you
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Answer:

Step-by-step explanation:

a.

Size of the population, N = 4000

Size of the sample, n = 40

n/N = 40/4000 = 0.01

0.01 is less than 0.05 and hence we would not us the finite population correction factor in calculating the standard error of the mean.

b.

Population standard deviation is σ = 8.2

<u>So, the standard error of x’ using the finite population correction factor is give by</u>

σ(x’) = √[(N - n)/(N - 1)] x (sigma/√n)

σ(x’) = √[(4000 - 40)/(4000 - 1)] x (8.2/√40)

σ(x’) = 1.29

<u>Standard error of x’ without using the finite population correction factor is</u>

σ(x’) = σ/√n

σ(x’) = 8.2/√40 = 1.2965

<u>There is little difference between the two values of the standard error. So we can ignore the population correction factor.</u>

c.

Let the population mean be μ

Probability that the sample mean will be within =-2 of the population mean is

P(μ– 2 < x’ < μ + 2)

At x’ = μ – 2 , we have

z = (μ – 2 – μ)/1.2965

z = -1.54

at x’ = μ  + 2, we have

z = (μ + 2 – μ)/1.2965

z = 1.54

<u>So the required probability is </u>

P(μ – 2 < x’ < μ + 2) = p(-1.54< z < 1.54)

P(μ – 2 < x’ < μ + 2) = p(z < 1.54) – p(z < -1.54)

P(μ – 2 < x’ < μ + 2) = 0.9382 – 0.0618

P(μ – 2 < x’ < μ + 2) = 0.8764

7 0
3 years ago
Please answer this im going to fail Rewrite the fraction as a decimal.
ivolga24 [154]

Step-by-step explanation:

it ia 76.92 is the percentage for 10/13

8 0
3 years ago
A large farm has 75 acres of wheat and 62.5 acres with a new job . The farm crew can harvest the wheat from 12 acres and the cor
RSB [31]

Answer:

All the fields will be harvested in 6.25 days

Step-by-step explanation:

because 75 ÷ 12 and 62.5 ÷ 12 is 6.25

6 0
3 years ago
For the members of a neighborhood meeting group, the probability of randomly selecting a member who likes to cook is 42%, the pr
Monica [59]

Answer: Probability of randomly selecting a member who likes to cook or likes to sew = 58%

Step-by-step explanation:

Since we have given that

Probability of a randomly selecting a member who likes to cook=P(C) = 42%

Probability of a randomly selecting a member who likes to sew =P(S)= 23%

Probability of a randomly selecting a member who likes to both cook and sew

P(C\cap S)=7\%

As we know the "Probability rules " :

P(C\cup S)=P(C)+P(S)-P(S\cap C)\\\\P(C\cup S)=42+23-7\\\\P(C\cup S)=58

So, Probability of randomly selecting a member who likes to cook or likes to sew = 58%



5 0
3 years ago
Who can prove that ? :D<br><br> prove that lim x about 0 (sin(x)/x)=1<br> by using sandwich theorem
earnstyle [38]
cos (x)  \leq \frac{sin (x)}{x}  \leq 1

Apply limit as x->0
8 0
3 years ago
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