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Olenka [21]
1 year ago
6

Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation one-halfx2 4x 8 = 0. whi

ch explanation could anderson provide?
Mathematics
1 answer:
amid [387]1 year ago
3 0

Anderson could provide 0.5x2 + 4x + 8 = 0 has exactly one real root if the discriminant is 0,

<h3>What is quadratic equation?</h3>

Any equation that can be rewritten in standard form as where x represents an unknown, a, b, and c represent known numbers, and where a 0 is true is a quadratic equation. As there is no ax2 term when a = 0, the equation is linear rather than quadratic.

<h3>What is discriminant?</h3>

A polynomial's discriminant is a quantity that depends on the coefficients and enables for some root attributes to be inferred without actually computing them. It is actually a polynomial function of the original polynomial's coefficients.

<h3>According to the given information:</h3>

0.5x^2 + 4x + 8 = 0

The discriminant is computed utilizing:

d = b^2 - 4ac

Thus, we have:

d = 4^2 - 4 * 0.5 * 8

Evaluate

d = 0

The equation has only one real root since the discriminant is 0,

To know more about discriminant visit:

brainly.com/question/16369636

#SPJ4

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Help me solve this problem step by step because I’m having a hard time
jarptica [38.1K]

Answer:

x=3, y=10

Step-by-step explanation:

in triangle KLN all the angles are equal making it an equilateral trianlge. GIven one side being 6, we know all the sides are 6 including the side with the expression y-4.

this means

y-4=6

y=10

Using the converse of the base angles theorem(meaning we know the base angles are congruent so the two sides are conguent), we know that

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Give the first ten terms of the following sequences. You can assume that the sequences start with an index of 1. Logs are to bas
Vitek1552 [10]

Answer:

a)

a1 = log(1) = 0 (2⁰ = 1)

a2 = log(2) = 1 (2¹ = 2)

a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849

a4 = log(4) = 2 (2² = 4)

a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322

a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)

a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807

a8 = log(8) = 3 (2³ = 8)

a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )

a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322

b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:

log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that

a1 = 1

a2 = 2

a3 = 3

a4 = 4

a5 = 5

a6 = 6

a7 = 7

a8 = 8

a9 = 9

a10 = 10

I hope this works for you!!

3 0
3 years ago
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