Pythagorean theorem.
a^2+b^2=c^2
This means that the square of the length of the 2 legs of a right triangle added together = the square of the length of the hypotenuses or diagonal.
If you know 2 of the values in the 3 variables a,b,c what would you do to find the missing variable value?
I will not write the exact answers to this problem. I think you can figure how to write it out yourselves.
Answer/Step-by-step explanation:
1. 7x + 2 = 5x + 22 (alternate interior angles are congruent)
Collect like terms
7x - 5x = -2 + 22
2x = 20
2x/2 = 20/2
x = 10
2. 13x - 6 = 10x + 24 (alternate interior angles are congruent)
Collect like terms
13x - 10x = 6 + 24
3x = 30
3x/3 = 30/3
x = 10
3. (12x + 26)° + 46° = 180° (same side interior angles are supplementary)
12x + 26 + 46 = 180
12x + 72 = 180
12x + 72 - 72 = 180 - 72
12x = 108
12x/12 = 108/12
x = 9
4. (5x + 5)° + 135° = 180° (same side interior angles are supplementary)
5x + 5 + 135 = 180
5x + 140 = 180
5x + 140 - 140 = 180 - 140
5x = 40
5x/5 = 40/5
x = 8
Answer:
y = 2x^2 − 4x + 5
y = 2(x^2 − 2x) + 5
y = 2(x^2 − 2x + 1 - 1) + 5
y = 2(x^2 − 2x + 1) + 5 - 2
y = 2(x - 1)^2 + 3
x = 1 is the axis of symmetry.
Do you agree?
<span>v(x)=(s/t)
= (3x - 6) / (-3x+6)
= [3(x-2)] / [-3(x-2)] --> 3 is factored out
= 1/-1 </span>---> common terms are cancelled out.
= -1 ---> This is the
simplified formula.
To find the domain, we equate the denominator to 0.
-3x+6 = 0
3x = 6
x = 2
Domain: all values except 2.
w(x)=(t/s)(x)
= (-3x+6)x / (3x-6)
= [-3x(x-2)] / [3(x-2)] --> 3 is factored out
= -x --> The common terms are cancelled out. This is the simplified formula.
Solving for domain:
3x-6 = 0
3x = 6
x = 2
Domain: all values except 2.