Well lets set up an equation 2 problems per second yields
for every second, x.
Now if we want the problems solved, y it will be equal to this product so
Now lets plug in 60 seconds, which is 1 minute
It can solve 120 algebra problems in 1 minute.
Each of them would have to see 5 movies to pay the same amount.
Explanation;
Members have to pay $30 a month just to have a lower admission fee. So members already start with a high price. If you add 7.95 together 5 times you get 39.75. This is the same as the members when you add the $30 admission fee to the 5 movies. (30+1.95....). That is how you find that both members and nonmembers will be paying the same amount after both watching 5 movies.
Answer:
a=-3
Step-by-step explanation:
5a+a=-10-8
6a=-18
a=-18/6
a=-3
Answer:
<u>Test the conjecture for 10 even numbers</u>
10 = 3 + 7
12 = 5 + 7
14 = 7 + 7
16 = 5 + 11
18 = 5 + 13
20 = 7 + 13
22 = 11 + 11
24 = 11 + 13
26 = 13 + 13
28 = 11 + 17
<u>Do you think the conjecture is true? Why or why not?</u>
I believe the conjecture is true because the sum of two odd numbers is an even number and you can find two prime odd numbers for every even number whose sum is that even number.
X = 4/5
y = 1/3
x+y = 4/5 + 1/3
x+y = 12/15 + 5/15
x+y = 17/15
