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Harlamova29_29 [7]
2 years ago
7

Helpppppppp plssss lol

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
3 0

Answer:

the answer is 3 because 7-4= 3

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PLEASE HELP IMMA FAIL
pshichka [43]

Answer:

4 sqrt(2) =c

Step-by-step explanation:

The base is the triangle

We can use the Pythagorean theorem to solve

a^2 + b^2 =c^2  where a and b are the legs and c is the hypotenuse

4^2 + 4^2 = c^2

2 * 4^2 = c^2

Take the square root of each side

sqrt(2 * 4^2) = sqrt(c^2)

sqrt(2) *sqrt( 4^2) = c

4 sqrt(2) =c

5 0
3 years ago
Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).
Vanyuwa [196]
L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)

R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R
5 0
2 years ago
Read 2 more answers
In ΔLMN, the measure of ∠N=90°, NL = 6. 8 feet, and LM = 9. 4 feet. Find the measure of ∠L to the nearest tenth of a degree.
egoroff_w [7]

Answer:

Step-by-step explanation:
The above is a right angled triangle
So you take the longest side
9.4^2 - 6.8^2
88.36- 46.24
sqrt of 42.12
6.4899

To the nearest tenth of a degree = 6.56.5ft



5 0
2 years ago
Is the sun even or odd 2+ 6
jeyben [28]
I believe it’s even can you tell me if I’m wrong pls
7 0
3 years ago
Are the two right triangles trs and wuv congruent? If so name the congruence postulate that applies
Nataly_w [17]
<span>Two figures are said to be congruent when they have the same shape and size or if one object is a mirror image of the other object.<span> The right triangles trs and wuv are congruent when they have equal lengths of the sides and having equal sides, angles should as well be equal with the two triangles.</span></span>
8 0
3 years ago
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