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krok68 [10]
3 years ago
6

Can someone solve this equation.

Mathematics
1 answer:
Marrrta [24]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

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Please help me and pls do both
Nana76 [90]

Answer:

7/36

Step-by-step explanation:

find the LCD   write all the numerators above the least common denominator

LCD is 36

4 +3 /36 =7/36

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Composite functions (Question in image)
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f(0) =  - 6 + 4 =  - 2 \\ g( - 2) = 4
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Increments of seven ​
BaLLatris [955]

Answer:

Specific Learning Outcomes:  

Solve problems that involve finding powers of a number

Description of mathematics:  

In this problem students work with powers of numbers and, as a consequence, come to understand what is happening to the numbers.  

Students also see how an apparently enormous and difficult calculation can be broken down into manageable parts. The students should come to realise that there are only a limited number of unit digits obtained when 7 is raised to a power. Further,  these specific digits 'cycle round' as the power of 7 increases. This cycle is 7, 9, 3, 1, 7, 9, …

The same is true of the digit in the tens place.

6 0
3 years ago
Choose the situation which would best be modeled by an exponential decay function.
Softa [21]
A) is the answer. The island in decaying by 10% each year, which means the amount will change within the period of the decay.

Hope this Helps! :)
7 0
3 years ago
Read 2 more answers
Which expression is equivalent to (4p^-4 q)^-2/ 10pq^-3?
Anit [1.1K]

Answer:

\dfrac{p^{7} q}{160}

Step-by-step explanation:

\dfrac{(4p^-4 q)^-2}{10pq^-3} =

= \dfrac{4^{-2}p^{-4\times (-2)} q^{-2}}{10pq^-3}

= \dfrac{4^{-2}}{10}p^{8-1} q^{-2-(-3)}

= \dfrac{1}{4^2 \times 10}p^{7} q^{-2 + 3}

= \dfrac{1}{160}p^{7} q

= \dfrac{p^{7} q}{160}

4 0
3 years ago
Read 2 more answers
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