Answer:
1c

1d

Step-by-step explanation:
From the question we are told that
The probability of telesales representative making a sale on a customer call is 
The mean is 
Generally the distribution of sales call made by a telesales representative follows a binomial distribution
i.e
and the probability distribution function for binomial distribution is
Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the mean is mathematically represented as

=> 
=> 
Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

=> 
=> ![P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95](https://tex.z-dn.net/?f=P%28%20X%20%5Cge%201%29%20%3D%201%20-%20%5B%20%5E%7Bn%7DC_0%20%2A%20%20%280.15%20%29%5E0%20%2A%20%20%281-%200.15%29%5E%7Bn-0%7D%5D%20%3E%200.95)
=> ![1 - [1 * 1* (0.85)^{n}] > 0.95](https://tex.z-dn.net/?f=%201%20-%20%5B1%20%20%2A%20%201%2A%20%20%280.85%29%5E%7Bn%7D%5D%20%3E%200.95)
=> ![[(0.85)^{n}] > 0.05](https://tex.z-dn.net/?f=%20%20%5B%280.85%29%5E%7Bn%7D%5D%20%3E%200.05)
taking natural log of both sides

=> 
The answer is 50 cents per fluid ounce and There is no option it so yeah 7 cups it’s 56 fluid ounces
Question 5: 4) 2006-2012
Question 6: 8x^2+8x+1
Question 7: 2) 2
Question 8: a is picture on top, b is picture on bottom
Answer:
744 in³
Step-by-step explanation:
Since you are filling the larger box with both rectangular prism and Styrofoam peanuts, you need to find the overall volume of the larger box and subtract the volume of the glass box to find the amount of space that the Styrofoam peanuts need to take up.
Volume (prism) = Bh, where B = area of the base, h = height
Larger Box: V = 10 x 10 x 15 = 1500 in³
Glass Box: V = 7 x 9 x 12 = 756 in³
1500 - 756 = 744 in³ of Styrofoam peanuts
Answer:
What is the wI-FI PASSWORD
Step-by-step explanation:
Friend me on
(2x+1)-1=0
Divide
2=0
Reitalizie
<em>2=0</em>
Reatomize
⊕∴∵
Reunatomize
2=0
It is not true
2=0