Answer:
10.5
Step-by-step explanation:
Answer:
Step-by-step explanation:
The given quadratic function is f(x)=2(2x^2+4x)+3
Multiplying through to open the brackets,
f(x)=4x^2 + 8x +3
To find the zeros, we will equate
f(x) = 0
Therefore,
4x^2 + 8x +3 = 0
Finding two numbers such that when we multiply them, it gives us 12xx^2 and when we add them, it gives us 8x, we have 6x and 2x. Therefore,
4x^2 + 8x +3 = 0 is expressed as
4x^2 + 2x + 6x +3 = 0
2x(2x + 2) +3(2x + 3) = 0
(2x +2)(2x +3) =0
f(x) = 2x +2)(2x +3)
Answer: Graph 10 and 12 are both functions while graph 13 is not a function
Step-by-step explanation: The best way to know if the graph is a function is by the vertical line test, if the points on the graph pass through the straight vertical line more than once, it is not a function, but if it passes though the line only once then it is a function. Now for the Domain and range, the best way to see it is as DomainX and RangeY, this is something I learned when I did functions, and it helped me a lot. Now if you look at 10 and 12, both go on infinitely, as they have no stopping point, meaning that the domain would be (-infinity, infinity), and for 13 you can simply put the coordinates for each point in a chart, with your X and Y, remember DomainX and RangeY, this should help you understand which is X and which is Y. I hope this helped a bit. Now for RangeY, for 10, look for the lowest number in the Y axis that the line goes, for this case its, -1, and then look for the highest number on the Y axis that the line goes, aka 3, now use this as a example and you can easily find 12's Range.
