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Lelechka [254]
3 years ago
11

HELP WILL MARK YOU BRAINLIEST HURRY IM ON A TIME LIMIT!’

Mathematics
2 answers:
Keith_Richards [23]3 years ago
6 0

(3x+5)+(x+3)=180

4x+8=180

4x=172

x=43

3(43)+5

<PQR=134

<SQR=46

levacccp [35]3 years ago
6 0

Answer:

\boxed {\angle PQR = 134\textdegree}

Step-by-step explanation:

Both angles are <u>Supplementary</u> (Two angles that add up to 180°). So, write an expression using the following measurements of both \angle PQR and \angle RQS and 180:

\angle PQR = 3x + 5

\angle RQS = x + 3

3x + 5 + x + 3 = 180

Solve:

3x + 5 + x + 3 = 180

4x + 5 + 3 = 180

4x + 8 = 180

4x + 8 - 8 = 180 - 8

4x = 172

\frac{4x}{4} = \frac{172}{4}

x = 43

-After you have the value of x, use it to the expression of \angle {PQR} to get the actual answer of \angle PQR:

-The value of x:

x = 43

-Solve for the measurement of \angle PQR:

3x + 5

3(43) + 5

129 + 5

134

-The measurement of \angle PQR:

\boxed {\angle PQR = 134\textdegree}

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Question:
DanielleElmas [232]

Given A room is half as long again as it is broad

Let the breadth of the room x m

length of the room x + x/2 = 3x/2m

Area of the room , x × 3x/2 =<em> 3x²/2m</em>

Given , cost of carpeting the room at Rs. 3.25m⁻²

So , total cost , 3x²/2 × 3.25

But , Total cost of carpeting is given as 175.50 so ,

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  • x² = 175.50 × 2 / 3.25 × 3
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let the height of the room H m

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8m² Area to be prepared = Area of four wall - area of two window and 1 door = (30H - 8) m²

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total cost of preparing wall is (30H - 8) × 1.40

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comparing , (30H - 8 ) × 1.40 = 240.80

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Hence, Dimensions of the room are lengths 9m , breadth 6m and height 6m

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