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Alex Ar [27]
1 year ago
12

Test

Mathematics
1 answer:
ziro4ka [17]1 year ago
6 0

Answer:

36m/3

Step-by-step explanation:

because I took the test and all ready know that answer

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Which statement correctly describes the end behavior of f(x)=ax+b, where a and b are positive numbers?
sergij07 [2.7K]

Answer:

The correct option is 2.

Step-by-step explanation:

The given function is

f(x)=ax+b

Where, a and b are positive numbers.

The given function is the slope intercept form of a linear function. Where a is the slope and b is y-intercept.

Since slope is positive therefore function approaches to infinity as x approaches to infinity and function approaches to negative infinity as x approaches to negative infinity.

It is also proved by using limits.

lim_{x\rightarrow \infty}f(x)=lim_{x\rightarrow \infty}(ax+b)

Apply limits.

lim_{x\rightarrow \infty}f(x)=a(\infty)+b=\infty

Similarly,

lim_{x\rightarrow -\infty}f(x)=lim_{x\rightarrow -\infty}(ax+b)

Apply limits.

lim_{x\rightarrow -\infty}f(x)=a(-\infty)+b=-\infty

Therefore option 2 is correct.

f(x)\rightarrow \infty \text{ as }x\rightarrow \infty

f(x)\rightarrow -\infty \text{ as }x\rightarrow -\infty

7 0
3 years ago
What does it mean for a sample to have a standard deviation of zero?
ki77a [65]
THE ANSWER IS SUPPOSED STAY THE SAME.
5 0
3 years ago
I need help on this question I need to see if I’m doing it the right way I think it’s *14+b=80
Lunna [17]

Answer:

b=66

Step-by-step explanation:

80-14 is 66, therefore b=66

5 0
3 years ago
I'm having a hard time with this. A new housing development extends 4 miles in one direction, makes a right turn, and then con-
Mademuasel [1]

Answer:

perimeter = 12 miles

area = 6 square miles

Step-by-step explanation:

Since it makes a right triangle, use the Pythagorean Formula.

3^2+4^2=c^2

9+16=c^2

25=c^2

5=c, so the hypotenuse of the right triangle is 5.

Perimeter = 3+4+5 = 12 miles

area = 1/2bh (1/2 base times height)

=1/2x3x4

=6

Area = 6 square miles

8 0
3 years ago
Please help, very confused!
My name is Ann [436]
\bf cot(\theta)=\cfrac{1}{tan(\theta)}
\qquad \qquad 
csc(\theta)=\cfrac{1}{sin(\theta)}\qquad \qquad sin(-\theta )=-sin(\theta )
\\\\\\
\textit{also recall }sin^2(\theta)+cos^2(\theta)=1\implies sin^2(\theta)=1-cos^2(\theta)\\\\
-------------------------------

\bf \cfrac{csc^2(x)-cot^2(x)}{sin(-x)cot(x)}\implies \cfrac{\frac{1}{sin^2(x)}-\frac{cos^2(x)}{sin^2(x)}}{-sin(x)\frac{cos(x)}{sin(x)}}\implies \cfrac{\frac{1-cos^2(x)}{sin^2(x)}}{-cos(x)}
\\\\\\
\cfrac{\frac{sin^2(x)}{sin^2(x)}}{-cos(x)}\implies \cfrac{1}{-cos(x)}\implies -sec(x)
7 0
3 years ago
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