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lesantik [10]
3 years ago
9

What is the missing statement in the proof?

Mathematics
1 answer:
Advocard [28]3 years ago
8 0
A statement that defines who you are as a professional and what you hope to
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Suppose a charity received a donation of $27.7 million. If this represents 31% of the charity's donated funds, what is the total
Annette [7]

Answer:

27.7 = 31%

0.89354838 = 1%

89.3548387 = 100%

89 million dollars

3 0
2 years ago
PLEASE HELP ASAP
Leno4ka [110]

Answer:

x=10

Step-by-step explanation:

we know that

If the lines m and n are parallel

then

130\° = (8x+50)\° ----> by corresponding angles

solve for x

8x=130-50\\8x=80\\x=10

7 0
3 years ago
What is 2÷8 , what will be the answer
AleksAgata [21]
The correct answer is .25
4 0
3 years ago
Read 2 more answers
6(14+x)=108, umm please help
My name is Ann [436]

Answer:

X = 4

I hope this helps

if you could, feel free to mark me Brainliest it would be much appreciated :D

4 0
3 years ago
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Max. penetration of a steel conduit.

The data of the sample

n= 45

sample mean X[bar]= 53.4

sample standard deviation S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= \frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }

t= 5.43

The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

I hope it helps!

4 0
3 years ago
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