The area of a square is length x width, but as all sides of a square are equal, then you can simply square the length of one side of the square.
The length of the square in your problem is 10 feet, so all sides have a length of 10 feet. You can write the problem for getting the area as 10x10 or 10-squared (10^2).
The answer would be 100 feet.
We can't see the angles so we can't help you :(
Maybe take a picture of the problem(or screenshot if it's online) and edit the post.
Answer:
8 sandwiches
Step-by-step explanation:
Answer: Part a: x=sqrt(104) in; Part b: x=sqrt(5) in
Step-by-step explanation:
Part a:
Because the figure has a right angle (signified by the square), it is a right triangle. Therefore, the Pythagorean Theorem, a²+b²=c² where c is the hypotenuse (longest side) and a and b are the legs (shorter sides), applies. Thus:
a²+b²=c²
The 15 in side is opposite the right angle, so it is the hypotenuse.
The 11 in side and x in side are not opposite the right angle, so they are legs.
11²+x²=15²
121+x²=225
(121+x²)-121=225-121
x²=104
sqrt(x²)=sqrt(104)
x=±sqrt(104)
Reject x=-sqrt(104) because a negative side length in a triangle is impossible. Therefore,
x=sqrt(104) in
Part b:
The figure is a right triangle. Therefore, the Pythagorean Theorem (a²+b²=c²) applies. Hence,
5²+(2x)²=(3x)²
25+4x²=9x²
(25+4x²)-4x²=9x²-4x²
25=5x²
5=x²
sqrt(5)=sqrt(x²)
x=±sqrt(5)
Reject x=-sqrt(5) because a negative side length is impossible.
The answer must be x=sqrt(5) in.
Answer:
D. X=-3, y=4
Step-by-step explanation:
-2x+3y=18 equation 1
x=-y+1 equation 2
-2(-y+1)+3y=18 replace x value of equation 2 into equation 1
2y-2+3y=18
5y=20
y=4
solve for x by replacing y value into either equation.
x=-y+1
x=-4+1
x=-3
