Answer:

Step-by-step explanation:
Given expression:
To simplify the expression, we will use the formula (a - b)² = a² - 2ab + b².
[Where "a and b" are the first and second term in (a - b)²]

In this case, the first term of (2x - 12)² is "2x" and the second term is "12".
![\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ [\small\text{First term = a = 2x; Second term = b = 12]}](https://tex.z-dn.net/?f=%5Crightarrowtail%20%282x%29%5E%7B2%7D%20-%202%282x%29%2812%29%20%2B%20%2812%29%5E%7B2%7D%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5B%5Csmall%5Ctext%7BFirst%20term%20%3D%20a%20%3D%202x%3B%20Second%20term%20%3D%20b%20%3D%2012%5D%7D)
Now, simplify the expression.



Answer:
C
Step-by-step explanation:
Answer:
In the pictures linked.
Step-by-step explanation:
The pictures I linked have the answers. Brainly wouldn't let me submit it because I apparently used bad words.
Answer:
y − 1 = -2 (x − 3)
Step-by-step explanation:
Point slope form is:
y − y₁ = m (x − x₁)
where m is the slope and (x₁, y₁) is a point on the line.
Given that m = -2 and (x₁, y₁) = (3, 1):
y − 1 = -2 (x − 3)
The ordered pair which makes both inequalities true is (-2, 2).
It is given that inequalities are
y < -x + 1 and y > x
For y < -x + 1
Substituting every ordered pair,
1) (-3, 5)
⇒ 5 < - (-3) + 1
⇒ 5 < 3 + 1
⇒ 5 < 4 is false
2) (-2, 2)
⇒ 2 < -(-2) + 1
⇒ 2 < 2 + 1
⇒ 2 < 3 is true
3) (-1, -3)
⇒ -3 < - (-1) + 1
⇒ -3 < 1 + 1
⇒ -3 < 2 is true
4) (0, -1)
⇒ -1 < -0 + 1
⇒ -1 < 1 is true
Now , for y > x
1) (-3, 5)
⇒ 5 > -3 is true
2) (-2, 2)
⇒ 2 > -2 is true
3) (-1, -3)
⇒ -3 > -1 is false
4) (0, -1)
⇒ -1 > 0 is false
Therefore ,the ordered pair which makes both inequalities true is (-2, 2).
To know more about Inequalities here
brainly.com/question/11612965
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