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3 years ago

Complete the statement 20ft 9 in = __in

Mathematics

2 answers:

RideAnS [48]3 years ago

6 0

Answer:

249 in

Step-by-step explanation:

Zarrin [17]3 years ago

3 0

The answer is 249 inches.

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Help right now i dont know this

maks197457 [2]

Answer:

Well the answer is 9

Step-by-step explanation:

4 time 1/2 equals 2 the add 7 and you get 9

Hope this helped! :)

6 0

3 years ago

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The highest point in North America is Mt. McKinley, and the lowest point is Death Valley. Mount McKinley is 6184 m above de leve

Karo-lina-s [1.5K]

It's probably 6300. Adding the two numbers together gives you 6271, which can be rounded up to 6300.

8 0

4 years ago

Read 2 more answers

Find the exact length of the third side. 65 16

JulsSmile [24]

I believe it is 63
a^2 + b^2=c^2
a^2+16^2=65^2
a^2+256=4225
a^2=3969
a=63

3 0

3 years ago

Consider the following. (See attachment)

Furkat [3]

Answer:

Area: 16

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Calculus

Derivatives

Derivative Notation

Integrals - Area under the curve

Trig Integration

Integration Rule [Fundamental Theorem of Calculus 1]: $\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Property [Addition/Subtraction]: $\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx$

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 8sin(x) + sin(8x)$

$\displaystyle y = 0$

Bounds of Integration: 0 ≤ x ≤ π

Step 2: Find Area Pt. 1

Set up integral: $\displaystyle A = \int\limits^{\pi}_0 {[8sin(x) + sin(8x)]} \, dx$
Rewrite integral [Integration Property - Addition/Subtraction]: $\displaystyle A = \int\limits^{\pi}_0 {8sin(x)} \, dx + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 8\int\limits^{\pi}_0 {sin(x)} \, dx + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Integrate [Trig Integration]: $\displaystyle A = 8[-cos(x)] \bigg| \limits^{\pi}_0 + \int\limits^{\pi}_0 {sin(8x)} \, dx$
[1st Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = 8(2) + \int\limits^{\pi}_0 {sin(8x)} \, dx$
Multiply: $\displaystyle A = 16 + \int\limits^{\pi}_0 {sin(8x)} \, dx$

Step 3: Identify Variables

Identify variables for u-substitution.

u = 8x

du = 8dx

Step 4: Find Area Pt. 2

[Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle A = 16 + \frac{1}{8}\int\limits^{\pi}_0 {8sin(8x)} \, dx$
[Integral] U-Substitution: $\displaystyle A = 16 + \frac{1}{8}\int\limits^{8\pi}_0 {sin(u)} \, du$
[Integral] Integrate [Trig Integration]: $\displaystyle A = 16 + \frac{1}{8}[-cos(u)] \bigg| \limits^{8\pi}_0$
[Integral] Evaluate [Integration Rule - FTC 1]: $\displaystyle A = 16 + \frac{1}{8}(0)$
Simplify: $\displaystyle A = 16$