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olga55 [171]
3 years ago
5

Eight days = _ hours Please tell me

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0
In order to answer this question, you need to know how many hours
there are in one day.  After that, it's a piece-o-cake.

                       1 day  =  24 hours .

Now you can make a table:

1 day  =  24 hours
2 days = 48 hours
3 days = 72 hours
4 days = 96 hours
5 days = 120 hours
6 days = 144 hours
7 days = 168 hours
8 days = 192 hours
9 days = 216 hours
10 days = 240 hours

My name is Ann [436]3 years ago
3 0
1 day = 24 hours. 
8 days equal 192 hours (multiply 8 days by 24). 

Or another way to think about it:
1 day          8 days
------------ = ----------
24 hours      x hours

Cross multiplying,
x = 8*24
x = 192
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Find the equation of the tangent line to the curve y equals left parenthesis x minus 3 right parenthesis superscript 7 baseline
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We have been given the expression to be y=(x-3)^7(x+1)^2

Since we need to find the tangent at a point, we will have to find the derivative of y as the slope of the tangent at a given point on the curve is always equal to value of the derivative at that point.

Thus, we have to find \frac{dy}{dx}=\frac{d}{dx} (x-3)^7(x+1)^2

We will use the product rule of derivatives to find \frac{dy}{dx}

Thus, y'=7(x-3)^6(x+1)^2+(x-3)^7\times2(x+1) (using the product rule which states that (fg)'=f'g+fg')

Taking the common factors out we get:

y'=(x-3)^6(x+1)(7(x+1)+2(x-3))

y'=(x-3)^6(x+1)(7x+7+2x-6)=(x-3)^6(x+1)(9x+1)

Thus, y' at x=4 is given by:

y'_{x=4}=Slope of the tangent of y at x=4=m

Thus, m=(4-3)^6(4+1)(9\times4+1)=185

Now, the equation of the tangent line which passes through (x_{1}, y_{1}) and has slope m is given by:

y-y_{1}=m(x-x_{1})

Thus, the equation of the tangent line which passes through (4,25) and has the slope 185 isy-25=185(x-4)

Which can be simplified to y=185x-740+25=185x-715

Thus, y=185x-715

This is the required equation of the tangent.

3 0
3 years ago
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pychu [463]

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Step-by-step explanation:

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