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harkovskaia [24]
3 years ago
15

How do you find the vertex of a quadratic equation in standard form?

Mathematics
2 answers:
Dafna11 [192]3 years ago
6 0

Answer:

Step-by-step explanation:

The standard form of a quadratic equation is ax² + bx + c, where<em> a</em> ≠ 0.

Given that the <u>axis of symmetry </u>occurs at <em>x</em> = <em>h,</em> then we can assume that the <em>h</em> coordinate of the vertex is the same as the x-coordinate in an ordered pair, (x, y).

In order to find the vertex, (h, k), use the following formula to solve for the value of <em>h</em>:

h = \frac{-b}{2a}.

<h3>Example:</h3>

To demonstrate this concept, let's say that we're given the following quadratic equation: 2x² + 8x + 8, where a = 2, b = 8, and c = 8. Substitute the values of a and b into the given equation for solving the x-coordinate (<em>h</em>) of the vertex:

h = \frac{-b}{2a}

h = \frac{-8}{2(2)} = \frac{-8}{4} = -2

Therefore, <em>h</em> = -2.

Next, substitute the value of <em>h</em> = -2 into the given quadratic equation in order to solve for its corresponding y-coordinate (<em>k </em>) of the vertex:

<em>k = </em>2x² + 8x + 8

where:  a = 2, b = 8, and c = 8

<em>k = </em>2(-2)² + 8(-2) + 8

<em>k </em>= 2(4) - 16 + 8

<em>k </em>= 8 - 16 + 8

<em>k </em>= 0

Therefore, the vertex of the quadratic equation, <em> </em>2x² + 8x + 8 is (-2, 0).

Yuki888 [10]3 years ago
3 0

Answer:

Get the equation in the form y = ax2 + bx + c.

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

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<h2>Answer:</h2>

The correct answer is:   Option: A

A.   85, 78, 80, 108, 46, 66, 68, 82, 72, 68

<h2>Step-by-step explanation:</h2>

It is given that:

The whisker ranges from 66 to 85.

The box ranges from 68 to 82 with the vertical bar inside the box at 75.

  • Hence, the minimum value of the box plot is: 66
  • Maximum value of box plot is: 85

Also,

  • The first quartile or the lower quartile i.e. Q_1 is: 68
  • The middle quartile or median i.e. Q_2 is: 75
  • The upper quartile or third quartile i.e. Q_3 is: 82

Also, it is given that:

One dot mark above forty-six.

One dot mark above one hundred and eight.

A)

On arranging the data in increasing order after removing outliers 46 and 108 we have:

 66    68    68    72    78    80    82     85  

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=75\\\\\\Q_3=81

As all the values matches the value defined.

Hence, this option is correct.

B)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    68    70   70   80    82     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=70\\\\\\Q_3=81

As the value of Q_2=70\neq 75.

Hence, this option is incorrect.

C)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    72    78   80   80    82     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=70\\\\Q_2=79\\\\\\Q_3=81

As the value of  Q_1,Q_2\ and Q_3 do not match.

Hence, this option is incorrect.

D)

On arranging the data in increasing order after removing 46 and 108 we have:

66    68    68    72   78   80    80     85

Hence, from this data we have:

Minimum value=66

maximum value=85

Q_1=68\\\\Q_2=79\\\\\\Q_3=80

As the value of  Q_3=80\neq 82 do not match.

Hence, this option is incorrect.

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