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nadezda [96]
3 years ago
14

Solve for x 7x^2=1008

Mathematics
2 answers:
andreev551 [17]3 years ago
7 0
This is the steps and the answer! I hope this helps!

Alex3 years ago
3 0

Answer:

x = {-12, 12}

Step-by-step explanation:

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How do you write ababaabaa in exponential form?​
NISA [10]

Answer:

\huge\boxed{a^6b^3}

Step-by-step explanation:

Because every term here is multiplied, simply count the number of 'a's and 'b's.

Hope it helps :) and let me know if you want me to elaborate.

6 0
2 years ago
What is 6 in the slope-intercept form
DochEvi [55]

Answer:

y= 1/4x + 1

Step-by-step explanation:

6 0
3 years ago
What is the distance from 3, 5) to 4.-12)?​
enyata [817]

Answer:

Step-by-step explanation:

P1 = (3.5,5)  in the form  (x1,y1)

P2 = (3.5,-12) in the form (x2,y2)

dist = sqrt[ (x2 - x1)^2 + (y2-y1)^2 ]

dist = sqrt[ (3.5-3.5)^2 + (-12-5)^2 ]

dist = sqrt [ 0  -17^2]

dist = 17

4 0
3 years ago
Given the arithmetic sequence with the following two
kondor19780726 [428]

Answer:

aₙ = -15 + 10 * (n-1)

Step-by-step explanation:

aₙ = a₁ + (n-1)*d       a₁: first term     d: common difference

a₅  a₁ + 4d =25 .... (1)

a₁₁  a₁ + 10d = 85   ...(2)

(2) - (1)     6d = 60

d = 10

a₁ = -15

Formula: aₙ = -15 + 10 * (n-1)

8 0
3 years ago
Use the counting techniques from the last chapter. A bag contains three red marbles, four green ones, one fluorescent pink one,
sergiy2304 [10]

Answer:

The probability that she gets all the red ones, given that she gets the fluorescent pink one, is P=0.0035 or 0.35%.

Step-by-step explanation:

Susan grabs four marbles at random.

We have to calculate the probabilities that he picks the 3 red ones, given that she already picked the fluorescent pink.

If it is given that the fluorescent pink is already picked, we are left with three red marbles, four green ones, two yellow ones, and four orange ones. A total of 13 marbles.

The probability that the second marble is red is 3 in 13.

The probability that the third marble is also red is 2 (the red marbles that are left) in 12 (the total amount of marbles left), as there is a picking without replacement.

The probability that the fourth marble is 1 in 11.

Then, the probability that the 3 red marbles are picked, is:

P=P_1\cdot P_2\cdot P_3=\dfrac{3}{13}\cdot \dfrac{2}{12}\cdot \dfrac{1}{11}=\dfrac{6}{1716}=0.0035

4 0
3 years ago
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