The error is that the graph is moving up two and over one. Basically using the slop 2/1 instead of 1/2. The slope is rise/run, so it should rise up 1 unit and run 2 units to the right.
Answer:
(h, k) is the point that represents the vertex of this absolute value function
Step-by-step explanation:
Recall that the vertex of an absolute value function occurs when the expression within the absolute value symbol becomes "zero", because it is at this point that the results in sign differ for x-values to the left and x-values to the right of this boundary point.
Therefore, in your case, the vertex occurs at x = h, and when x = h, then you can find the y-value of the vertex by looking at what f(h) renders:
f(h) = a | h - h | + k = 0 + k = k
Then the point of the vertex is: (h, k)
Answer:
false
Step-by-step explanation:
(-7-2) > (6-14)
-7-2 = -9
6-14 = -8
-9 is not > -8, because -9 is farther to the left on a number line. So, this statement would be false.
I'd help if I could, but unfortunately, this is the one area of math that I suck at.
Answer:
C
Step-by-step explanation:
