Answer:
![Total = 1.02n](https://tex.z-dn.net/?f=Total%20%3D%201.02n)
Step-by-step explanation:
Given
![Earnings = n](https://tex.z-dn.net/?f=Earnings%20%3D%20n)
--- <em>not 296</em>
![Total = n + 0.02n](https://tex.z-dn.net/?f=Total%20%3D%20n%20%2B%200.02n)
Required
Simplify the expression for total earning
The total amount is derived from:
![Total = Earnings + Raise * Earnings](https://tex.z-dn.net/?f=Total%20%3D%20Earnings%20%2B%20Raise%20%2A%20Earnings)
![Total = n + 2\% * n](https://tex.z-dn.net/?f=Total%20%3D%20n%20%2B%202%5C%25%20%2A%20n)
Express percentage as decimal
![Total = n + 0.02 * n](https://tex.z-dn.net/?f=Total%20%3D%20n%20%2B%200.02%20%2A%20n)
Now, we can solve further:
![Total = n + 0.02n](https://tex.z-dn.net/?f=Total%20%3D%20n%20%2B%200.02n)
![Total = 1.02n](https://tex.z-dn.net/?f=Total%20%3D%201.02n)
<em>Hence, the simplified expression is 1.02n</em>
X + x - 32 = 180
2x - 32 = 180
2x = 212
x = 106
x - 32 = 106 - 32 = 74
the other 2 angles = 90
C: 30
You replace the value of Y in 5Y with 6 and multiply 5 by 6 to get 30.
Answer:
$19,201.09
Step-by-step explanation:
The future value of the annuity due can be found using any of a number of apps, calculators, or spreadsheets. It can also be found using the formula ...
A = P(1 +r)((1 +r)^n -1)/r
where P is the annual payment, r is the annual interest rate, and compounding is yearly for n years.
A = 2535(1.1418)(1.1418^5 -1)/0.1418 ≈ 19,201.09
The value will be $19,201.09.
Hey there! I'm happy to help!
Here is our equation.
![2y-3x=10](https://tex.z-dn.net/?f=2y-3x%3D10)
Let's add 3x to both sides.
![2y=3x+10](https://tex.z-dn.net/?f=2y%3D3x%2B10)
Divide both sides by 2.
![y=\frac{3}{2}x+5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7Dx%2B5)
Here is slope intercept form.
![y=mx+b\\m=slope\\b=y-intercept](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5Cm%3Dslope%5C%5Cb%3Dy-intercept)
So, we can just find those two things in the equation, and here are our answers.
![y=\frac{3}{2}x+5\\m=\frac{3}{2}\\b=5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7Dx%2B5%5C%5Cm%3D%5Cfrac%7B3%7D%7B2%7D%5C%5Cb%3D5)
The graph is down below. If our y-intercept is 5, then one of our points is (0,5). You can then plug a random x-value into the formula to find another point and then draw the line going through the two points.
![y=\frac{3}{2}(2)+5\\y=3+5\\y=8\\(2,8)](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B3%7D%7B2%7D%282%29%2B5%5C%5Cy%3D3%2B5%5C%5Cy%3D8%5C%5C%282%2C8%29)
Have a wonderful day and keep on learning! :D