I really need help finding the solution!!

Mathematics

1 answer:

Mrac [35]3 years ago

3 0

Answer:

-0.5 is not a solution

2 is a solution

Step-by-step explanation:

To check if something is a solution of the equation, you need to substitute the value in place of the variable

15 + 2y = -12 - 4y

15 + 2(-0.5) = -12 - 4(-0.5)

15 - 1 = -12 + 2

14 ≠ -10 ∴ -0.5 is not a solution

5 - 2(3x + 5) = 3 - 10x

5 - 2[3(2) + 5] = 3 - 10(2)

5 - 2(6 + 5) = 3 - 10(2)

5 - 12 - 10 = 3 - 120

-17 = -17 ∴ 2 is a solution

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Select all irrational numbers.

Maurinko [17]

Answer:

OPTION A

OPTION B

OPTION C

Step-by-step explanation:

Irrational numbers are the subset of real numbers. Their decimal representation neither form a pattern nor terminate.

OPTION A: $\sqrt{\frac{1}{2}}$

This is equal to $\frac{1}{\sqrt{2}}$ .

$\sqrt{2} = 1.414...$ is non-terminating. So, it is an irrational number. Hence, the reciprocal of an irrational number would also be irrational. So, OPTION A is irrational.

OPTION B: $\sqrt{\frac{1}{8}}$

This is equal to $\frac{1}{2\sqrt{2}}$ . Using the same logic as Option A, we regard OPTION B to be irrational as well.

OPTION C: $\sqrt{\frac{1}{10}}$

This is equal to $\frac{1}{\sqrt{5}\sqrt{2}}$ .

Both $\sqrt{5}$ and $\sqrt{2}$ are irrational. So, the product and the reciprocal of the product is irrational as well. So, OPTION C is an irrational number.

OPTION D: $\sqrt{\frac{1}{16}}$

16 is a perfect square and is a rational number. $\frac{1}{\sqrt{16}}$ = $\frac{1}{4}$ . This is equal to 0.25, a terminating decimal. So, OPTION D is a rational number.