All categories

2 years ago

Solve z/5 - 6 = 2 2/3

Mathematics

1 answer:

almond37 [142]2 years ago

4 0

The answer is x= 36 2/3

You might be interested in

Explain when you must write the number 1, and when you do not need to.

stepan [7]

Answer:

The number 1 is not necessary when expressing powers of one. For example, you needn't write "5" as $5^{1}$ .

Step-by-step explanation:

7 0

3 years ago

Help me math gods helpppp meme

trasher [3.6K]

Answer:

the 3rd one from top

Step-by-step explanation:

because the coefficient is largest

7 0

2 years ago

Read 2 more answers

The equation 9 x 2 − 12 x + 4 = 0 9 x 2 − 12 x + 4 = 0 has how many different solutions?

Hatshy [7]

We have the equation:

$9x^2-12x+4=0$

so:

$a=9\qquad b=-12\qquad c=4$

and:

$\Delta=b^2-4ac=(-12)^2-4\cdot9\cdot4=144-144=\boxed{0}$

This equation has one solution.

5 0

2 years ago

Match each function

Elis [28]

Answer:

* The degree of the function is 4 and the leading coefficient is positive

f(x) = (x + 6)(2x - 3)(x - 1)²

* The degree of the function is 5 and the leading coefficient is negative

f(x) = (x - 2)²(-2x - 1)²(-x + 1)

* The degree of the function is 6 and the leading coefficient is negative

f(x) = (-x + 1)³(x + 2)²(x - 3)

* The degree of the function is 5 and the leading coefficient is positive

f(x) = (-2x + 1)²(x - 3)²(x + 1)

Step-by-step explanation:

∵ f(x) = (x + 6)(2x - 3)(x - 1)²

∵ (x)(2x)(x²) = 2x^4

∴ The degree of the function is 4

∴ The leading coefficient is positive ⇒ (2)

∵ f(x) = (x - 2)²(-2x - 1)²(-x + 1)

∵ (x)²(-2x)²(-x) = (x²)(4x²)(-x) = -4x^5 ⇒ (neglect -ve with even power)

∴ The degree of the function is 5

∴ The leading coefficient is negative ⇒ (-4)

∵ f(x) = (-x + 1)³(x + 2)²(x - 3)

∵ (-x)³(x)²(x) = (-x³)(x²)(x) = -x^6

∴ The degree of the function is 6

∴ The leading coefficient is negative ⇒ (-1)

∵ f(x) = (-2x + 1)²(x - 3)²(x + 1)

∵ (-2x)²(x)²(x) = (4x²)(x²)(x) = 4x^5

∴ The degree of the function is 5

∴ The leading coefficient is positive ⇒ (4)

6 0

3 years ago

Square ABCD is dilated by a scale factor of 2 with the center of dilation at the origin to form square ABCD . What are the coord

kobusy [5.1K]

Answer:

B'(16,14)

Step-by-step explanation:

In square ABCD, A(2,7) C(8,1) D(2,1). First, find the coordinates of the vertex B. From the attached diagram you can see that CD=6 units and is parallel to the x-axis, AD=6 units and is parallel to the y-axis. So, B(8,7).

The origin O is the center of dilation, 2 is the scale factor. The rule of the dilation is

(x,y)→(2x,2y)

Thus,

B(8,7)→B'(16,14) (see attached figure).

8 0

2 years ago