Consider the vertices of parallelogram JKLM with vertices J(2,2) , K(5,3) , L(5,-3) and M(2,-4).
Perimeter JKLM = Length JK + Length KL + Length LM + Length JM
Length JK = (2,2) (5,3)
The length(or distance) between two points say and is given by the distance formula:
Now, length JK =
= units
Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.
Therefore, LM = units
Now, length KL =
= 6 units
Since, JKLM is a parallelogram. In parallelogram opposite sides are equal in length.
Therefore, JM = 6 units
Perimeter of JKLM = + + 6 + 6
= 2 + 12
= 18.324
Rounding to the nearest tenth, we get
= 18.3 units.
Therefore, the perimeter of JKLM is 18.3 units.
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Answer:
y = -(x+4)² +7
Step-by-step explanation:
I find it convenient to factor the leading minus sign from the first two terms, then work with what's left.
... y = -(x² +8x) -9
Now, add the square of half the x-coefficient inside parentheses. Add the opposite of that amount outside parentheses.
... y = -(x² +8x +4²) -9 +4²
... y = -(x +4)² +7 . . . . . . . . . rewrite parentheses as a square; collect terms
Answer:
31/3 or 31 over 3
Step-by-step explanation:
If you do the whole number (10) times the denominator (bottom number of the fraction,in this case 3) the add the numerator (top number of the fraction,in this case 1) you will get your improper fraction.