Answer: Choice A) Add 3.8 to both sides of the equation
Explanation:
If we knew the value of w, then we would replace it and apply PEMDAS.
However, we don't know the value of w, so we undo each step of PEMDAS going backwards.
We start with the "S" of PEMDAS, and undo the subtraction. To undo subtraction, you apply addition. To undo that "minus 3.8" we add 3.8 to both sides.
The solution to the algebraic equation, −0.4x − 3.1 = 5.9, is:<u> x = -22.5</u>
Given the algebraic equation, −0.4x−3.1 = 5.9, to solve for x, follow the steps below:
−0.4x − 3.1 = 5.9
−0.4x − 3.1 + 3.1 = 5.9 + 3.1
-0.4x = 9
- Divide both sides by -0.4
-0.4x/-0.4 = 9/-0.4
x = -22.5
Therefore, the solution to the algebraic equation, −0.4x − 3.1 = 5.9, is:<u> x = -22.5</u>
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Learn more here:
brainly.com/question/16864747
Multiply both variables individually by the multiplied variable (x)... and you find yourself with -fx + hx.... Remember to bring that negative integer along too or the answere that I have without a negative integer won't count... I hope this clarified your understanding and question. As always good spiruts
Answer:
The original price was 520
Step-by-step explanation:
To find this, we first need to note that we paid 75% of the price. This is because we took 25% off from the original. Now we take the price we paid and divide it by the percentage of it which we paid. This will give us the original price.
390/75% = Total
390/.75 = Total
520 = Total
Answer:
Initial temperature;
432.76
Common ratio;
-0.067
Equation;

Step-by-step explanation:
In this scenario, the time in minutes represents the independent variable x while the temperature of the pizza represents the dependent variable y.
The analysis is performed in Ms. Excel. The first step is to obtain a scatter plot of the data then finally inserting an exponential trend line to obtain the required equation.
The Ms. Excel output is shown in the attachment below. To obtain the initial temperature we substitute x = 0 in the equation. On the other hand, the common ratio is the exponent in the equation.