Answer:
x=4
Step-by-step explanation:
3x+x - 2x + 8= 3x + x
4x- 2x +8 = 4x
2x + 8= 4x
8= 2x
x=4
Answer: i think (4n+1)^2(4n-1)^2 isnt a multiple of 8 for all integers of n because:
(4n + 1)²(4n - 1)²
= [(4n + 1)(4n - 1)]²
= (16n² - 1)²
= 16².n².n² - 2.16.n² + 1
= 8n²(32n² - 4) + 1
can see 8n²(32n² - 4) is a multiple of 8 but 1 isnt a multiple of 8
=> (4n + 1)²(4n - 1)² isnt a multiple of 8 for all integers of n.
Step-by-step explanation:
Answer:
There are N students in the class.
We know that ONLY ONE of the inequalities is true:
N < 10
N > 10
N < 22
N > 22
We want only one of these four inequalities to be true.
Remember that if we have:
x > y
y is not a solution, because:
y > y is false.
Then:
If we take N = 10, then:
N < 22
Is the only true option.
While if we take N = 22
N > 10
is the only true option.
So there are two possible values of N.
Since the triangles are the same, just flipped that means that all angles and segments are the same as well
I'm not sure if that's the "correct" way to prove it but that's why they're equal