Given:
The frequency distribution table.
To find:
The mean average score on a test.
Solution:
The frequency distribution table is
x a xa
y b yb
z c zc
Sum a+b+c xa+yb+zc
Now, the mean average score on the test is
Therefore, the mean average score on the test is 
.
Answer:
First one is 6 16/21
Second one is 3 14/15
Step-by-step explanation:
Answer:
<h2>x = 3</h2>
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
The quotient is 18
Answer:
Step-by-step explanation:
Rearrange each function to solve for x.
Switch x and y,
The resulting equation is the inverse function.
A:
f(x) = y = 5+x
x = y-5
y = x-5
f⁻¹(x) = x-5
g(x) = 5-x ≠ f⁻¹(x)
g(x) is not the inverse of f(x).
:::::
B:
f(x) = y = 2x-9
x = (y+9)/2
y = (x+9)/2
f⁻¹(x) = (x+9)/2
g(x) = (x+9)/2 = f⁻¹(x)
g(x) is the inverse of f(x).
:::::
C:
f(x) = y = 2/x - 6
x = 2/(y+6)
y = 2/(x+6)
f⁻¹(x) = 2/(x+6)
g(x) = (x+6)/2 ≠ f⁻¹(x)
:::::
D:
f(x) = y = x/3 + 4
x = 3y - 12
y = 3x - 12
f⁻¹(x) = 3x - 12
g(x) = 3x - 4 ≠ f⁻¹(x)
g(x) is not the inverse of f(x).
