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yan [13]
3 years ago
14

You are given a graph G = (V, E) with positive edge weights, and a minimum spanning tree T = (V, E’) with respect to these weigh

ts; you may assume G and T are given as adjacency lists. Now suppose the weight of a particular edge e ∈ E is modified from w(e) to a new value ŵ(e). You wish to quickly update the minimum spanning tree T to reflect this change, without recomputing the entire tree from scratch. There are four cases. In each case give a linear-time algorithm for updating the tree.
(a) e ∉ E’ and ŵ(e) > w(e).
(b) e ∉ E' and ŵ (e) < w(e).
(c) e ∈ E' and ŵ (e) < w(e).
(d) e ∈ E' and ŵ (e) > w (e)
Computers and Technology
1 answer:
matrenka [14]3 years ago
7 0
C vraiment très facile
Si tu a besoin d’aide recontacter moi
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Write a function listLengthOfAllWords which takes in an array of words (strings), and returns an array of numbers representing t
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Answer:

   public static int[] listLengthOfAllWords(String [] wordArray){

       int[] intArray = new int[wordArray.length];

       for (int i=0; i<intArray.length; i++){

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           intArray[i]=lenOfWord;

       }

       return intArray;

   }

Explanation:

  1. Declare the method to return an array of ints and accept an array of string as a parameter
  2. within the method declare an array of integers with same length as the string array received as a parameter.
  3. Iterate using for loop over the array of string and extract the length of each word using this statement  int lenOfWord = wordArray[i].length();
  4. Assign the length of each word in the String array to the new Integer array with this statement intArray[i]=lenOfWord;
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A Complete Java program with a call to the method is given below

<em>import java.util.Arrays;</em>

<em>import java.util.Scanner;</em>

<em>public class ANot {</em>

<em>    public static void main(String[] args) {</em>

<em>       String []wordArray = {"John", "James", "David", "Peter", "Davidson"};</em>

<em>        System.out.println(Arrays.toString(listLengthOfAllWords(wordArray)));</em>

<em>        }</em>

<em>    public static int[] listLengthOfAllWords(String [] wordArray){</em>

<em>        int[] intArray = new int[wordArray.length];</em>

<em>        for (int i=0; i<wordArray.length; i++){</em>

<em>            int lenOfWord = wordArray[i].length();</em>

<em>            intArray[i]=lenOfWord;</em>

<em>        }</em>

<em>        return intArray;</em>

<em>    }</em>

<em>}</em>

This program gives the following array as output: [4, 5, 5, 5, 8]

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