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adoni [48]
3 years ago
11

Consider the graph shown.

Mathematics
1 answer:
enot [183]3 years ago
5 0

Answer:

slope- 3/4. equation- y=3/4x+1

Step-by-step explanation:

to get the equation, you use the formula y=mx+b, where m is the slope and b is the y intercept, which means it is where the line touches the y axis

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What is the equation of a circle with center (-3, -1) that contains the point (1, 2)?
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hmmm what's the radius anyway?   well, we know that there's a point at 1,2 that is on the circle's path...hmmmm what's the distance from the center to that point?  well, is the radius, let's check then.

\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -3}}\quad ,&{{ -1}})\quad &#10;%  (c,d)&#10;&({{ 1}}\quad ,&{{ 2}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}&#10;\\\\\\&#10;r=\sqrt{[1-(-3)]^2+[2-(-1)]^2}\implies r=\sqrt{(1+3)^2+(2+1)^2}&#10;\\\\\\&#10;r=\sqrt{16+9}\implies r=\sqrt{25}\implies r=5

so, what's the equation of a circle with center at -3, -1 and a radius of 5?

\bf \textit{equation of a circle}\\\\ &#10;(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2&#10;\qquad &#10;\begin{array}{lllll}&#10;center\ (&{{ h}},&{{\quad  k}})\qquad &#10;radius=&{{ r}}\\&#10;&-3&-1&5&#10;\end{array} &#10;\\\\\\\&#10;[x-(-3)]^2+[y-(-1)]^2=5^2\implies (x+3)^2+(y+1)^2=25
7 0
3 years ago
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