Answer:
$9$
Step-by-step explanation:
Given: Thea enters a positive integer into her calculator, then squares it, then presses the $\textcolor{blue}{\bf\circledast}$ key, then squares the result, then presses the $\textcolor{blue}{\bf\circledast}$ key again such that the calculator displays final number as $243$.
To find: number that Thea originally entered
Solution:
The final number is $243$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $243$ must be $324$.
As previously the number was squared, so the number before $324$ must be $18$.
As previously the $\textcolor{blue}{\bf\circledast}$ key was pressed,
the number before $18$ must be $81$
As previously the number was squared, so the number before $81$ must be $9$.
Answer:
D
Step-by-step explanation:
irdk sorry if its wrong :(
Please go into more detail about the question then u will be able to help you
Answer:
Only equation 1 and 2 are equal.
Step-by-step explanation:
2 (x + 4)2 = 2
2( x² + 8x+ 16) = 2 Applying the square formula
2x² + 16x+ 32 = 2
2x² + 16x+ 32 -2= 0
2x² + 16x+ 30 = 0
2( x² + 8x+ 15)= 0 Taking 2 as common
x2 + 8x + 15 = 0------------eq 1
x2 + 8x + 15 = 0-------------eq 2
(x − 5)2 = 1
x²-10x+25= 1 Applying the square formula
x²-10x+25- 1= 0
x²-10x+24= 0-------------eq 3
x2 − 10x + 26 = 0 -------------eq 4
3(x − 1)2 + 5 = 0
3( x²-2x+1)+5= 0 Applying the square formula
3x²-6x+3+5= 0
3x²-6x+ 8= 0-------------eq 5
3x2 − 6x + 8 =1
3x2 − 6x + 8 -1=0
3x2 − 6x + 7 =0-------------eq 6
