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ANTONII [103]
3 years ago
9

What are the zeros of the function?

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0
The answer is c and e. To find the zeros of a function and they give you options like this, just plug them into the equation until they equal 0.
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Drag the phrases into the box to match each expression. 4x – 5 4 (x – 5) 4 ( x + 5) 5 less than the sum of 4 and a number 5 less
Gnoma [55]

Answer:

4x – 5

4 (x – 5)

4 ( x + 5)

5 less than the sum of 4 and a number

5 less than the product of 4 and a number

the product of 4 and the difference of a number and 5

4 more than the sum of a number and 5

5 more than the product of 4 and a number

the product of 4 and the sum of a number and 5

4 more than 5 less than a number

5 0
3 years ago
1 ) Tim earns $12.50 an hour cleaning houses. If he works from 8:00am to 2:00pm,
AVprozaik [17]

Answer:

$75

Step-by-step explanation:

First, we will find how many hours he worked. 8:00-12:00 is 4 hours, and 12:00-2:00 is 2 hours, so he worked a total of 6 hours.

Next, we have to multiply the hours worked by his hourly wage.

12.50*6=75

8 0
3 years ago
Read 2 more answers
Francis mixes 3/8 gal of white paint, 2 7/8 gal of blue paint, and 1 1/4 gal of red paint.
Rina8888 [55]

List all the info:

3/8 gallon of white paint

2 7/8 gallon of blue paint

11/4 gallon of red paint

First, let’s answer the first question.

Francis has made _____ gal of paint when he first mixes the three colors.

Add all the gallons of paints together and you get 6. So, Francis has made 6 gal of paint when he first mixes the three colors.

Now for the second blank. All you have to do is do 6 divided by 3/8 which is 16. So, The constant of proportionality of white paint to gallons of mixed paint is 16.

Lastly, you will have to do is 3/8 x 7 = 2 5/8. (Im not too sure about this part though, but the rest I‘m pretty confident about)

3 0
3 years ago
Lowering powers write in terms of first power of cosine. Cos^6
yaroslaw [1]

The main identity you need is the double angle one for cosine:

\cos^2x=\dfrac{1+\cos2x}2

We get

\cos^6x=(\cos^2x)^3=\left(\dfrac{1+\cos2x}2\right)^3=\dfrac{(1+\cos2x)^3}8

Expand the numerator to apply the identity again:

\cos^6x=\dfrac{1+3\cos2x+3\cos^22x+\cos^32x}8

\cos^6x=\dfrac{1+3\cos2x+3\left(\frac{1+\cos2(2x)}2\right)+\cos2x\left(\frac{1+\cos2(2x)}2\right)}8

\cos^6x=\dfrac{1+3\cos2x+\frac32+\frac32\cos4x+\frac12\cos2x(1+\cos4x)}8

\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{16}\cos2x\cos4x

Finally, make use of the product identity for cosine:

\cos2x\cos4x=\dfrac{\cos6x+\cos2x}2

so that ultimately,

\cos^6x=\dfrac5{16}+\dfrac7{16}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos2x+\dfrac1{32}\cos6x

\cos^6x=\dfrac5{16}+\dfrac{15}{32}\cos2x+\dfrac3{16}\cos4x+\dfrac1{32}\cos6x

4 0
4 years ago
Find the vertex of the parabola. then write the function in vertex form
Marysya12 [62]

Answer:

you need to post a picture or explain more

7 0
4 years ago
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