To determine the centroid, we use the equations:
x⁻ =
1/A (∫ (x dA))
y⁻ = 1/A (∫ (y dA))
First, we evaluate the value of A and dA as follows:
A = ∫dA
A = ∫ydx
A = ∫3x^2 dx
A = 3x^3 / 3 from 0 to 4
A = x^3 from 0 to 4
A = 64
We use the equations for the centroid,
x⁻ = 1/A (∫ (x dA))
x⁻ = 1/64 (∫ (x (3x^2 dx)))
x⁻ = 1/64 (∫ (3x^3 dx)
x⁻ = 1/64 (3 x^4 / 4) from 0 to 4
x⁻ = 1/64 (192) = 3
y⁻ = 1/A (∫ (y dA))
y⁻ = 1/64 (∫ (3x^2 (3x^2 dx)))
y⁻ = 1/64 (∫ (9x^4 dx)
y⁻ = 1/64 (9x^5 / 5) from 0 to 4
y⁻ = 1/64 (9216/5) = 144/5
The centroid of the curve is found at (3, 144/5).
Answer:
Step-by-step explanation:
X is 1 y is -4
Which gets the following:
X(1) + y(-4) = -3
x(1) + 2(-4) = -7
Answer:
Step-by-step explanation:
The dominant term of this function is x^4. The graph of x^4 starts in Quadrant II and continues in Quadrant I.
If we have y = -x^4, the graph starts in Quadrant III and continues in Quadrant IV. This is the end behavior for f(x)=-x^4+5x^3-3.
Answer:
on the first triangle it is equal, 1.5 on the left of it is half of 3 on the right triangle, 5 on the left is half of 10 on the right triangle. so the answer is 8 becuase each side on the left is 2 times the side on the right
Step-by-step explanation:
hope this helps
Answer:
Step-by-step explanation
Hello!
3x/4 + 6=42
3x/4=42-6 = 36
3x = 36*4
3x = 144
x= 144/3 =48
3/4 of 48 = (48*3) / 4 =36
36+6=42
the original number is 48
