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3 years ago

HELP PLEAAAAAAAAAAASE

Mathematics

1 answer:

dalvyx [7]3 years ago

4 0

The answer is option B.
Because it can't be chocolate.

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Victoria has 2.50 pounds of bell peppers and the cost is $1.25. What is the price for 1 pound of bell peppers?

AleksAgata [21]

Answer:

The price of one pound of bell peppers is $0.6.

Step-by-step explanation:

This problem is equivalent to the following:

"if 10 oranges cost $20, how much does 1 orange cost? "

and the answer to that question is:

price of 1 orange = $20/ 10 oranges = $2 per orange.

Put simply, we divided the total price by the total number of items, and we shall do the same thing for the case of bell peppers:

price of 1 pound = $1.25/ 2.5 pounds = $0.5/ pound.

The price for 1 pound of bell peppers is $0.5.

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3 years ago

100 POINTS: ANSWER PROPERLY WITH STEPS SHOWN FOR BRAINLIEST AND POINTS!!!!!!!!!!!! GST AND PST VALUES ARE BASED ON CANADA ONTARI

neonofarm [45]

Answer:

yes i agree with you!!!

Step-by-step explanation:

5 0

3 years ago

Help me on 2 plsssss

julia-pushkina [17]

3.6 to the power of 5

3 0

2 years ago

Read 2 more answers

Changes in airport procedures require considerable planning. Arrival rates of aircrft are important factors that muct be taken i

Irina18 [472]

Answer:

a) 0.1558

b) 0.7983

c) 0.1478

Step-by-step explanation:

If we suppose that small aircraft arrive at the airport according to a Poisson process at the rate of 5.5 per hour and if X is the random variable that measures the number of arrivals in one hour, then the probability of k arrivals in one hour is given by:

$\bf P(X=k)=\displaystyle\frac{(5.5)^ke^{-5.5}}{k!}$

(a) What is the probability that exactly 4 small aircraft arrive during a 1-hour period?

$\bf P(X=4)=\displaystyle\frac{(5.5)^4e^{-5.5}}{4!}=0.1558$

(b) What is the probability that at least 4 arrive during a 1-hour period?

$\bf P(X\geq4)=1-P(X$

(c) If we define a working day as 12 hours, what is the probability that at least 75 small aircraft arrive during a working day?

If we redefine the time interval as 12 hours instead of one hour, then the rate changes from 5.5 per hour to 12*5.5 = 66 per working day, and the pdf is now

$\bf P(X=k)=\displaystyle\frac{(66)^ke^{-66}}{k!}$

and we want P(X ≥ 75) = 1-P(X<75). But

$\bf P(X$

hence

P(X ≥ 75) = 1-0.852 = 0.1478

7 0

3 years ago

How can x² = x² + 2x + 9 be set up as a system of equations? (1 point)

koban [17]

Answer: 2

Step-by-step explanation:

Each of the two sides of the equation is set equal to y

4 0

1 year ago