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Sunny_sXe [5.5K]
3 years ago
14

2. Circle C, has center (0,0) and radius 2.

Mathematics
1 answer:
adell [148]3 years ago
8 0

Answer:

2. x ²  +  y ² =  4

3. x² + y² = 23

Step-by-step explanation:

The equation of a circle with center  

( a , b )  and radius  r  is:

( x − a )²   +  ( y − b ) ² =  r ²

Explanation:

Here,

 a = 0 ,  b = 0 ,  r = 2  

The equation is:

( x -0 ) ² +  ( y -0 ) ² =  ( 2  ) ²

that is:  x ²  +  y ² =  4  

Thus:

x ²  +  y ² =  4

3. Each point on a circle has the same distance from the center. This distance is the radius  r  of the circle.

 Here, ( -3 , 4 )  is a point on the circle, meaning that the radius of the circle is the distance between  ( 0 , 0 ) , the center, and  ( -3 , 4 ) .

thus  a circle centered on the origin will have an equation of:

x² + y² =r²

And,  ( -3 , 4 )  lies on the circle, we have:

(-3)² + (4)² = r²

9 + 14 = 23

substituting;

x² + y² = 23

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Lines 3x-2y+7=0 and 6x+ay-18=0 is perpendicular. What is the value of a?
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Answer:

\boxed{\sf a = 9 }

Step-by-step explanation:

Two lines are given to us which are perpendicular to each other and we need to find out the value of a . The given equations are ,

\sf\longrightarrow 3x - 2y +7=0

\sf\longrightarrow 6x +ay -18 = 0

Step 1 : <u>Conver</u><u>t</u><u> </u><u>the </u><u>equations</u><u> in</u><u> </u><u>slope</u><u> intercept</u><u> form</u><u> </u><u>of</u><u> the</u><u> line</u><u> </u><u>.</u>

\sf\longrightarrow y = \dfrac{3x}{2} +\dfrac{ 7 }{2}

and ,

\sf\longrightarrow y = -\dfrac{6x }{a}+\dfrac{18}{a}

Step 2: <u>Find </u><u>the</u><u> </u><u>slope</u><u> of</u><u> the</u><u> </u><u>lines </u><u>:</u><u>-</u>

Now we know that the product of slope of two perpendicular lines is -1. Therefore , from Slope Intercept Form of the line we can say that the slope of first line is ,

\sf\longrightarrow Slope_1 = \dfrac{3}{2}

And the slope of the second line is ,

\sf\longrightarrow Slope_2 =\dfrac{-6}{a}

Step 3: <u>Multiply</u><u> </u><u>the </u><u>slopes </u><u>:</u><u>-</u><u> </u>

\sf\longrightarrow \dfrac{3}{2}\times \dfrac{-6}{a}= -1

Multiply ,

\sf\longrightarrow \dfrac{-9}{a}= -1

Multiply both sides by a ,

\sf\longrightarrow (-1)a = -9

Divide both sides by -1 ,

\sf\longrightarrow \boxed{\blue{\sf a = 9 }}

<u>Hence </u><u>the</u><u> </u><u>value</u><u> of</u><u> a</u><u> </u><u>is </u><u>9</u><u> </u><u>.</u>

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Step-by-step explanation:

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