The answer is 2x+3 <span>Twice a certain number is tripled. The resulting number is _____.
2x + 3
2x - 3
(2x)3
1/3(2x)</span>
First you can factor out a -2 from the original expression
-2(4x²-27x-70)
Then, use any method you're familiar with to factor (4x²-27x-70)= (x+2)(4x-35) ***
***I used the "AC method" Let me know if you'd like me to explain this part
So the expression -2(x+2)(4x-35) is the same as the original
9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
Answer:
180
Step-by-step explanation:
formulae=H×L×W so....5×9×4=180
Answer:
detailed one
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