LIST THE 7 BEST PROGRAMMING MOVIES 2020-2021.

In an office there is a unisex bathroom with n toilets. The bathroom is open to both men and women, but it cannot be used by men

Gnesinka [82]

Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <stdlib.h>

#include <pthread.h>

#include <semaphore.h>

int mcount,wcount;

sem_t x,y,z,wsem,msem,cap;

void delay(void)

{

int i;

int delaytime;

delaytime = random();

for (i = 0; i<delaytime; i++);

}

void *woman(void *param)

{

sem_wait(&z);

sem_wait(&wsem);

sem_wait(&y);

wcount++;

if(wcount==1)

{ sem_wait(&msem); }

sem_post(&y);

sem_post(&wsem);

sem_post(&z);

sem_wait(&cap);

printf("woman in!\n");

delay();

printf("\twoman out!\n");

sem_post(&cap);

sem_wait(&y);

wcount--;

if(wcount==0)

{ sem_post(&msem); }

sem_post(&y);

}

void *man(void *param)

{

sem_wait(&z);

sem_wait(&msem);

sem_wait(&x);

mcount++;

if(mcount==1)

{ sem_wait(&wsem); }

sem_post(&x);

sem_post(&msem);

sem_post(&z);

sem_wait(&cap);

printf("\t\tman in!\n");

delay();

printf("\t\t\tman out!\n");

sem_post(&cap);

sem_wait(&x);

mcount--;

if(mcount==0)

{sem_post(&wsem);}

sem_post(&x);

}

int main(void)

{

int i;

srandom(60);

mcount = 0;

wcount = 0;

sem_init(&x,0,1); // for sem_init, initial value is 3rd argument

sem_init(&y,0,1);

sem_init(&z,0,1);

sem_init(&wsem,0,1);

sem_init(&msem,0,1);

sem_init(&cap,0,4); // eg. cap initialized to 4

pthread_t *tid;

tid = malloc(80*sizeof(pthread_t));

// You can use your cobegin statement here, instead of pthread_create()

// I have forgone the use of pthread barriers although I suppose they would nicely imitate the functionality of cobegin.

// This is merely to retain simplicity.

for(i=0;i<10;i++)

{

pthread_create(&tid[i],NULL,woman,NULL);

}

for(i=10;i<20;i++)

{

pthread_create(&tid[i],NULL,man,NULL);

}

for(i=0;i<20;i++)

{

pthread_join(tid[i],NULL);

}

return(0);

}

5 0

3 years ago

Kitchen Gadgets

Scilla [17]

Answer:

hehe

Explanation:

7 0

3 years ago

The incident results in huge losses of revenue as a result their mobile app service is withdrawn. Investigators discovered a vul

zlopas [31]

Answer:

The attackers used the code injection

Explanation:

<em>Because, the HMTL5 allows data and code to be mixed together, making code injection attacks possible. </em>

6 0

3 years ago

Write code to take a String input from the user, then print the first and last letters of the string on one line. Sample run: En

Ainat [17]

<h2>Answer:</h2>

//import the Scanner class to allow for user input

import java.util.Scanner;

//Begin class definition

public class FirstAndLast{

//Begin the main method

public static void main(String []args){

//****create an object of the Scanner class.

//Call the object 'input' to receive user's input

//from the console.

Scanner input = new Scanner(System.in);

//****create a prompt to tell the user what to do.

System.out.println("Enter the string");

//****receive the user's input

//And store it in a String variable called 'str'

String str = input.next();

//****get and print the first character.

//substring(0, 1) - means get all the characters starting

//from the lower bound (index 0) up to, but not including the upper

//bound(index 1).

//That technically means the first character.

System.out.print(str.substring(0,1));

//****get and print the last character

//1. str.length() will return the number of character in the string 'str'.

//This is also the length of the string

//2. substring(str.length() - 1) - means get all the characters starting

// from index that is one less than the length of the string to the last

// index (since an upper bound is not specified).

// This technically means the last character.

System.out.print(str.substring(str.length()-1));

} // end of main method

} //end of class definition

<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java

3 0

3 years ago

How to see if your computer has bluetooth?

RUDIKE [14]

Assuming you're running Windows, click the start button, and then search for "Device Manager" (or open CMD or PowerShell and type devmgmt.msc). Look at the list of devices. If Bluetooth is there, you have it; if it's not there, you don't.

3 0

3 years ago