1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vilka [71]
2 years ago
13

Aiden measured a campground and made a scale drawing. The scale of the drawing was 9 inches = 3 yards. What is the scale factor

of the drawing?
Simplify your answer and write it as a fraction.
Mathematics
1 answer:
lions [1.4K]2 years ago
8 0

Answer:2/3

Step-by-step explanation: just divide them as a improper fraction

You might be interested in
Corey has a piece of fabric that is 1/4 yard long. He cuts the length into 2 equal pieces. Write an expression for the length, i
MrRissso [65]

Answer:The length of each piece of fabric is 1/8 yards.

Step-by-step explanation:

Corey has a piece of fabric that is 1/4 yard long. He cuts the length into 2 equal pieces. This means that he cut 1/4 yards of fabric into two equal pieces.

An expression for the length, in yards, of each piece of fabric will be

Let the length of the fabric be x in yards. Also, let the length of each piece of fabric be y in yards. It becomes

y = x/2

Since x = 1/4

y =( 1/4)/ 2 = 1/4 × 1/2

y = 1/8

The length of each piece of fabric is 1/8 yards.

4 0
3 years ago
Hey guys!!! I forgot how to do this :/ lol<br> whats 10+4÷2?
Travka [436]

Answer:

12

Step-by-step explanation:

8 0
3 years ago
Find the first partial derivatives of the function. f(x, y) = ax + by/ cx + dy
Marina86 [1]
<span>The partial derivative of the given function with respect to x is a - by/cx2 + dy/dx In this derivative the terms in the with x is only considered other or treated as constant The partial derivative of the given function with respect to y is b/cx+ d2y/dx. In this derivative the terms in the with x is only considered other or treated as constant</span>
5 0
3 years ago
The scores on an exam are listed. If a teacher wants to explain how poorly the class did on the test, would she use the mean, me
Natasha_Volkova [10]
Mean because the mean is an average. That gives an overall understanding of what the entire class did.
4 0
3 years ago
Read 2 more answers
Find equations for the lines through the point (a,
Free_Kalibri [48]
The line y = mx + c has a slope of m.

Parallel line:
A parallel line will also have a slope of m, and should be of the form
y = mx + k
Because the line passes through the point (a,b), therefore
ma + k = b
k = b - ma
The equation of a parallel line is
y = mx + b - ma
   = m(x-a) + b

Perpendicular line:
A perpendicular line will have a slope of -1/m, because the product of slopes should be -1.
The equation for a perpendicular line is of the form
y = -(1/m)x + k
Because the line passes through (a,b), therefore
-(1/m)a + k = b
k = b + a/m
The equation for a perpendicular line is
y = -(x/m) + b + a/m 
   = -(1/m)(x-a) + b

Answer:
Parallel line: y=m(x-a)+b
Perpendicular line: y=- \frac{1}{m}(x-a)+b

3 0
3 years ago
Other questions:
  • What’s the solution to 8+1/3x=-1
    13·1 answer
  • A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.
    12·2 answers
  • Jeffrey's recipe for oatmeal muffins calls for 2 1/4 cups of oatmeal and makes one dozen muffins. If he makes 1 1/2 dozen muffin
    11·1 answer
  • (3x-4) (6x+7) <br><br> Multiply those binomials.
    7·2 answers
  • What is the rate of change and initial value for the linear relation that includes the points shown in the table?
    12·2 answers
  • Multiply. x + 4x + 2 2x2 + 3x – 4​
    14·1 answer
  • What is the sum of degrees of each vertex for a tree with 6 vertices?
    13·2 answers
  • I need help. plz help​
    11·2 answers
  • Tobin is solving the equation 3 (x minus 1.25) = 11.25. His work is shown below.
    12·2 answers
  • 2(-1)+y=3<br><br><br> What is the answer
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!