Question

What are the focus and directrix of the parabola that is the graph of the function f(x)=x²?

Answer 1

Answer:

Step-by-step explanation:

Given

$y=x^2$

comparing it with standard equation $x^2=4ay$

so 4a=1

$a=\frac{1}{4}$

so Focus of parabola is (0,0)

directrix

y=-a

here $a=\frac{1}{4}$

$y=-\frac{1}{4}$