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2 years ago

Whiat is the converse of the statement below?

Mathematics

2 answers:

Ede4ka [16]2 years ago

7 0

Answer:the answer is B

Step-by-step explanation:

Inga [223]2 years ago

4 0

Hi there!

The converse of this statement is y=>x.

Hope this helps! ;)

~Just an emotional teen who listens to her favorite song "Try Everything"

$SilentNature ;)$

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ElenaW [278]

Normally when there is similar terms and when you have to figure out if it is factorable or prime you must first begin factoring it and if it does not work it is prime.
Hope this helps, ask me if you have any questions.

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2 years ago

What is the difference & similarities of matter and mass ?

Tamiku [17]

that differences are that mass is a measurement of the amount of matter something contains and mass is measured by using a balance comparing a known amount of matter to an unknow of matter

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2 years ago

Read 2 more answers

16.

777dan777 [17]

Answer:

21,800 milliliters

Step-by-step explanation:

Here's a trick.

King Henry Died By Drinking Chocolate Milk.

King = Kilo, Henry = Hecto, Died = Deka, By = Base (liters, grams, meters), Drinking = Deci, Chocolate = Centi, Milk = Milli.

This helps to remember the order so you can move the decimal over the proper amount of times.

If you are starting at the base, and need to move to milli, you will move the decimal place 3 places to the right.

So for 21.8 liters = 21,800 milliliters

6 0

2 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .