Answer:
It gives a new string
Explanation:
In programming; when two or more strings are concatenated by a concatenating operator, the result is always a new string.
From the question, we have that
str1 = "Good
str2 = "Evening"
Let's assume that + is the concatenating operator;
str1 + str2 = "Good" + "Evening" = "GoodEvening"
The result of concatenating str1 and str2 is a new string "GoodEvening" while str1 and str2 still maintain their original string value of "Good" and "Evening"
Which of the following application architecture do you suggest as the best option for email for an organization? Consider small, medium and large organizations to provide your suggestions.
1. Two-tier client-server
2. web-based
Answer:
2. Web based
Explanation:
Web based applications provides cloud based email solutions provider that benefits small organisation as much as big organisations because the investment is minimal and affordable and gives no problem in deployment of resources to manage services with no risk.
It provides multiple point access by providing email solutions that enables multiple point of access gives rise to flexibility of access by members of the organisation.
It provides powerful admin control which makes management of email services easy and provides high security for services.
Explanation:
rand() function is used to generate random integers between the range 0 to RAND_MAX.So if we divide the the rand() function by RAND_MAX the value returned will be 0.
You cannot do RAND_MAX + 1 the compiler will give error integer overflown.
To generate an integer with a range.You have to do like this:
srand(time(0));
int a=-1*(rand() % (0 - 5245621) +1);
cout <<a;
This piece of code will return an integer within the range 0 to -5245622.
Answer:
A.Costs
Explanation:
Transaction processing systems are used in business for operational support. This information system processes data as transactions usually in automated manner.
Automation causes efficiency and reduced human intervention, which will end up <em>reduced operational costs</em>.
The correct answer should be A. Delete