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Kaylis [27]
3 years ago
11

The binary search algorithm cannot be used to search an array that is not sorted does twice as much work as sequential search on

the average case must be written using recursion is slower than sequential search when the item being searched for is not in the array
Computers and Technology
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

Option A => cannot be used to search an array that is not sorted

Explanation:

The reason for choosing ‘option a’ is that, the actual working mechanism of binary search is to sort the array first then choose a middle element and compare the given search element with the help of middle element. Let us deeply understand how this sorting and choosing middle element does the work of search.

So this middle element is the key pointer which tells the system that the matching element might be present either to the list of values which are less than middle element or it would be present in the right side / greater than middle element. So, it would search only in the list satisfying the middle element. So it is always necessary to sort the element.

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The 3 parts of the CPU are
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What is the value of |-10|
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Let C(x) be the statement "x has a cat," let D(x) be the statement "x has a dog," and let F(x) be the statement "x has a ferret.
allsm [11]

Answer:

See attached for answer and explanation

Explanation:

Note: the question is incomplete, consider the statements below as the statements to be expressed in terms of C(x), D(x), F(x), quantifiers, and logical connectives.

(a) A student in your class has a cat, a dog, and a ferret.

(b)  All students in your class have a cat, a dog, or a ferret.

(c) Some student in your class has a cat and a ferret, but not a dog.

(d) No student in your class has a cat, a dog, and a ferret.

(e) For each of the three animals, cats, dogs, and ferrets, there is a student in your class who has this animal as a pet.

7 0
3 years ago
he timing device in an automobile’s intermittent wiper system is based on an RC time constant and utilizes a 0.500-μF capacitor
Tatiana [17]

Answer:

4000k-ohm to 10,000k-ohm

Explanation:

As we know that time constant for an RC circuit is t=RC

Putting the values of t we can get the range of varaiable resistor as;

t=RC

Putting t=2 we get the first value of the range for the variable resistor

2=R*0.500*10^-6

R=2/(0.500*10^-6)

R=4*10^6

R=4000k-ohm

Now putting t=5 we get the final value for the range of variable resistor

t=RC

5=R*0.500*10^-6

R=5/(0.500*10^-6)

R=10*10^6

R=10,000k-ohm

So variable resistance must be made to vary in the range from 4000k-ohm to 10,000k-ohm

5 0
3 years ago
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