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3 years ago

What is the measure of NRS?

Mathematics

1 answer:

never [62]3 years ago

6 0

Answer:

Step-by-step explanation:

(7x - 1) + 79° = 21x + 8

• An exterior angle of a triangle is equal to the sum of its two interior opposite angles.

$(7x - 1) +79 = 21x + 8 \\ 7x - 1 + 79 = 21x + 8 \\ 7x + 78 = 21x + 8 \\ 78 - 8 = 21x - 7x \\ 70 = 14x \\ \frac{70}{14} = x \\ 5 = x \\$

NRS = 21x + 8

$21x + 8 \\ 21(5) + 8 \\ 105 + 8 \\ {113}^{o}$

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What is 8 percent of 10,000of 1 year

Lerok [7]

8% means 0.08
"of" usually means"times" in math
8% of 10,000 = 0.08 x 10,000 = <em>800 .</em>

I don't understand what "10,000 of 1 year" means.
But again, "of" usually means"times" in math.
So maybe your question means "0.08 x 10,000 x 1 year" = <em>800 years

</em>

3 0

3 years ago

five times the larger of two consecutive odd integers is equal to one more than eight times the smaller. What is the larger inte

Margarita [4]

The formula to find two consecutive odd integers is x + (x+2)
5(x+2) = 1 + 8(x)
5x + 10= 1 + 8x
10= 1 + 3x
9=3x
x = 3
Answer : the larger integer is 5(3+2) which is 25

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3 years ago

A survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the resul

pav-90 [236]

Answer:

95% confidence interval for the proportion of the adults who were opposed to the death penalty is (0.668, 0.704).

Step-by-step explanation:

We are given that a survey asked whether respondents favored or opposed the death penalty for people convicted of murder. Software shows the results below, where X refers to the number of the respondents who were in favor.

X = 1,790

N = 2,610

$\hat p$ = Sample proportion = X/N = 0.6858

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion = 0.6858

n = sample of respondents = 2,610

p = population proportion

<em>Here for constructing 95% confidence interval we have used One-sample z proportion statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at

2.5% level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

P( $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ < p < $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.95

<u>95% confidence interval for p</u> = [ $\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ , $\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} }$ ]