All categories

2 years ago

Express 6.86 as a mixed number

Mathematics

2 answers:

irinina [24]2 years ago

8 0

6 43/50
this is the answer
hope it helped

Natali5045456 [20]2 years ago

6 0

For u to understand better

You might be interested in

PRACTICE 1 Lesson 15-1

VladimirAG [237]

6 is wrong, a rhombus is a diamond shape

8 0

2 years ago

Read 2 more answers

Hello please help i’ll give brainliest

IgorC [24]

Answer:

The difference between the shortest and longest fish is 12 inches.

Hope this helped!!

6 0

2 years ago

Read 2 more answers

The width of a rectangle is 3 units less than the length. The area of the rectangle is 28 units. What is the width, in units, of

KATRIN_1 [288]

Answer:

Step-by-step explanation:

Let's call the width W and the length L.

We know the width is 3 less than the length, so:

W = L - 3

And we know the area is 28, so:

28 = WL

If we solve for L in the first equation:

L = W + 3

And substitute into the second equation:

28 = W (W + 3)

28 = W² + 3W

0 = W² + 3W - 28

0 = (W + 7) (W - 4)

W = -7, 4

Since W can't be negative, W = 4 units.

8 0

3 years ago

If $500 yields $43.49 in simple interest over 7 years, what is the annual rate?

Annette [7]

Answer:

1.24 %

Step-by-step explanation:

500 * x * 7 = 43.49

x = 43.49/(7*500) = .0124 1.24 %

8 0

2 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify

irina [24]

Answer:

x-coordinates of relative extrema = $\frac{-1}{2}$

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

$f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}$

Differentiate with respect to x

$f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}$

$f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}$

Differentiate f'(x) with respect to x

$f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1$

At x = $\frac{-1}{2}$ ,

$f''\left ( \frac{-1}{2} \right )=\frac{4\left ( -1+4\left ( \frac{-1}{2} \right ) \right )}{3\left ( \frac{-1}{2} \right )^{\frac{5}{3}}}>0$

We know that if $f''(a)>0$ then x = a is a point of minima.

So, $x=\frac{-1}{2}$ is a point of minima.

For inflexion points:

Inflexion points are the points at which f''(x) = 0 or f''(x) is not defined.

So, x-coordinates of the inflexion points are 0, 1

7 0

2 years ago