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nexus9112 [7]
2 years ago
14

a ball is thrown straight downward with a speed of 0.80 meters per second. what is the speed of the ball 0.60 seconds after it i

s released? [ignore air resistance.]
SAT
1 answer:
san4es73 [151]2 years ago
7 0

The speed of the ball 0.60 seconds after it is released is 6.8 m/s.

Newton's law of motion is given by:

v = u + gt

where v is the final velocity, u is the initial velocity, g is the acceleration due to gravity and t is the time.

Given that:

u = 0.8 m/s, g = 10 m/s², t = 0.6s. Hence:

v = 0.8 + 10(0.6)

v = 6.8 m/s

Therefore the speed of the ball 0.60 seconds after it is released is 6.8 m/s.

Find out more at: brainly.com/question/8648874

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Determine the empirical formula of a compound containing 47. 37 grams of carbon, 10. 59 grams of hydrogen, and 42. 04 grams of o
Effectus [21]

Considering the definition of empirical formula, the empirical formula is C₃H₈O₂ and the molecular formula is C₉H₂₄O₆.

<h3>Definition of empirical formula</h3>

The empirical formula is the simplest expression to represent a chemical compound, which indicates the elements that are present and the minimum proportion in whole numbers that exist between its atoms, that is, the subscripts of chemical formulas are reduced to the most integers. small as possible.

<h3>Empirical formula in this case</h3>

In this case, you have:

  • Carbon (C): 47.37 grams
  • Hydrogen (H): 10.59 grams
  • Oxygen (O):  42.04 grams

Then it is possible to calculate the number of moles of each atom in the molecule, taking into account the corresponding molar mass:

  • Carbon (C): \frac{47.37 grams}{12 \frac{g}{mole} }= 3.95 moles
  • Hydrogen (H): \frac{10.59 grams}{1 \frac{g}{mole} }= 10.59 moles
  • Oxygen (O):  \frac{42.04 grams}{16 \frac{g}{mole} }= 2.63 moles

The empirical formula must be expressed using whole number relationships, for this the numbers of moles are divided by the smallest result of those obtained. In this case:

  • Carbon (C): \frac{3.95 moles}{2.63 moles }= 1.5
  • Hydrogen (H): \frac{10.59 moles}{2.63 moles }= 4
  • Oxygen (O):  \frac{2.63 moles}{2.63 moles }= 1

Finally, since in the empirical formula the numbers of moles must be expressed in whole numbers, the ratio of atoms is multiplied by some number with which everything is obtained in simple whole numbers (in this case by 2):

  • Carbon (C): 1.5× 2= 3
  • Hydrogen (H): 4× 2= 8
  • Oxygen (O):  1× 2= 2

Therefore the C: H: O mole ratio is 3: 8: 2

Finally, the empirical formula is C₃H₈O₂.

<h3>Molecular formula</h3>

To obtain the molecular formula you must relate its molecular weight (PMc) with the molecular weight of the empirical formula (PMfe).

PMfe= PM (C₃H₈O₂)= 76 g/mole

The molar mass of the compound (PMc) was determined to be 228.276 g/mol. Dividing this mass PMc by the molar mass of the empirical formula PMfe gives:

228.276 g/mol ÷ 76 g/mole= 3

This means that in the molecular formula there are 3 unit formulas (empirical formulas), so it is necessary to multiply the number of all atoms by 3.

Then, the molecular formula is C₉H₂₄O₆.

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If you were asked to take a shot in a landscape area which includes the large fields and mountains, what kind of shot you will p
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The kind of shot i will take if asked to take a shot of a landscape area is called; Landscape Shot

<h3>Understanding Landscape Photography</h3>

Landscape photography is defined as the practice of capturing a natural or outdoor scene in an artful or compelling way in order to get the attention the viewer's.

There are different types of making photography but landscape photography is simply one of the most appreciated genres of photography and as such when taking shots of large fields and mountains we will take a landscape shot.

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