Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Answer:
The 2 numbers are 32 and 65.
Step-by-step explanation:
x + y = 97 where x and y are the 2 numbers.
x = 2y + 1
Substituting for x in the first equation:
2y + 1 + y = 97
3y = 96
y = 32.
So x = 2y + 1 = 64 + 1 = 65.
Heres an example x2- 16 when u solve or factor u should get the difference of two squares of (x+2) (x-2)
Step-by-step explanation:
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