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3 years ago

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under what circumstances is the ERR more appropriate method than IRR to evaluate a project ANSWER is C WHEN THE LENGTH OF THE PR

OJECT IS GREATER THAN 20 YEARS If the future worth is greater than zero what does it mean about the project

1 answer:

Vilka [71]3 years ago

3 0

Answer:

yes

Step-by-step explanation:

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1354

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Calculate the volume of the following object:

frozen [14]

Answer:

262.44 cubic metres.

Step-by-step explanation:

First, we can calculate the volume of the cylinder by doing pi * r^2 * h. In this case, r is 5 / 2 and h is 7.

pi * (5/2)^2 * 7 = pi * 25/4 * 7 = pi * 6.25 * 7 = pi * 43.75 = 3.14159265 * 43.75 = 137.4446784 cubic m.

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137.4446784 + 125 = 262.4446784, which is about 262.44 cubic metres.

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3 years ago

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HELP ASAP!! A recipe calls for 2.3 cup of milk. if you make 3 1/2 times the recipe, how much milk do you need?

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2 years ago

A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4

skad [1K]

Answer:

a) $\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

b) The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got:

$\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401$

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And for this case after replace the values and with the sample mean already calculated we got:

$s=0.0036$

If we assume that the data represent a population then the standard deviation would be given by:

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}$

And then the deviation would be:

$\sigma =0.00319$

3 0

3 years ago