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Answer:
Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.
Step-by-step explanation:
Answer:
-5/7
Step-by-step explanation:
remember slope is eqaul to rise over run.
6-11 = -5 so it rose down by 5 units
10 - 3 = 7 so it ran 7 units
thus
slope= -5/7
Answer:
A(y=3) B(y = -2) C(y= 4)
A' (y = 3) B(y= -2) C(y= 4)
Step-by-step explanation:
