Answer:
2.5
Step-by-step explanation:
We can see that the original length of RS is 2 units. The length of R'S' is 5 units.
2 * x = 5
2x = 5
x = 5/2
x = 2.5
Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So



has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
I came up with when x=9, y=6.
Answer:
$1.40
Step-by-step explanation:
5.00-0.80=4.20
4.20 ÷ 3= 1.40