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3 years ago

Find the length of x

Mathematics

1 answer:

fomenos3 years ago

4 0

Answer:

x=5/2

Step-by-step explanation:

We can use ratios of similar triangles to help solve the problem.

side x 5

-------- = --------------- = ---------------

hypotenuse 4 8

Using cross products

x*8 = 4 * 5

8x = 20

Divide each side by 8

8x/8 = 20/8

x = 5/2

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Evaluate expression if B=3equals three. 1/2 (b to the third power -1)

Nuetrik [128]

The answer is 2.375 or 2 3/8

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3 years ago

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beks73 [17]

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4 years ago

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Which undefined geometric term is described as a two-dimensional set of points that has no beginning or end? a;line b;distance c

Dmitrij [34]

Answer:

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Step-by-step explanation:

8 0

3 years ago

A ray of light with intensity lo falls vertically on the sur face of the sea and at ten meters deep its intensity is 10/3. Assum

seropon [69]

Answer:

intensity = $\frac{Io}{15}$

intensity = $\frac{Io}{30}$

depth = 333.33 m

Step-by-step explanation:

given data

deep = 10 m

intensity = Io

intensity = Io/3

to find out

intensity of light at 50 m and 100 m and 1/100 of initial intensity remain ?

solution

we know here that intensity is inversely proportional to deep so

intensity = k × $\frac{1}{Deep}$ .................1

here k is constant

so we have given 10 m deep so

$\frac{Io}{3}$ = $\frac{k}{10}$

so k = Io × $\frac{10}{3}$ ................2

so from equation 1 when 100 m deep and 50 m deep

intensity = k × $\frac{1}{Deep}$

intensity = Io × $\frac{10}{3}$ × $\frac{1}{50}$

intensity = $\frac{Io}{15}$

and

intensity = Io × $\frac{10}{3}$ × $\frac{1}{100}$

intensity = $\frac{Io}{30}$

and

at intensity Io/100

intensity = k × $\frac{1}{Deep}$

$\frac{Io}{100}$ = Io × $\frac{10}{3}$ × $\frac{1}{D}$

D = 333.33 m

so depth = 333.33 m

3 0

3 years ago

If r = 2 and s= 7, what is the value of |r| - |s|?

andrew11 [14]

Since r = 2, and s = 7, we would substitute r and s with 2 and 7:

| r | - | s | = | 2 | - | 7 | = 2 - 7 = -5

The answer is -5

7 0

3 years ago